1. Calculate the force of gravitational attraction between a concrete ball (mı 2.0 x 103 kg) and a steel ball (m2 = 2.0 x 104 kg) whose centers are separated by 4.0 m.

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
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1. Calculate the force of
gravitational attraction
between a concrete ball (m1 =
2.0 x 103 kg) and a steel ball
(m2 = 2.0 x 104 kg) whose
centers are separated by 4.0
m.
2. Calculate the magnitude of
force of gravitational
attraction between two metal
balls used in men's shot put
competition, each of mass
7.26 kg and whose centers are
separated by a distance of 24
cm.
3. Find the force of attraction
between the Earth and the
moon using the following
data:
• Mass of the moon = 7.35 x
1022 kg|
• Mass of the earth = 5.98 x
1024 kg
• Ave. distance between
their centers = 3.84 x108 m
%3D
Transcribed Image Text:1. Calculate the force of gravitational attraction between a concrete ball (m1 = 2.0 x 103 kg) and a steel ball (m2 = 2.0 x 104 kg) whose centers are separated by 4.0 m. 2. Calculate the magnitude of force of gravitational attraction between two metal balls used in men's shot put competition, each of mass 7.26 kg and whose centers are separated by a distance of 24 cm. 3. Find the force of attraction between the Earth and the moon using the following data: • Mass of the moon = 7.35 x 1022 kg| • Mass of the earth = 5.98 x 1024 kg • Ave. distance between their centers = 3.84 x108 m %3D
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