A spring stretches 0.350 m when a 0.750 kg mass is hung from it. The spring is then stretched an additional 0.250 m from this equilibrium point and released. Determine (a) the spring constant, k, (b) the maximum velocity of the mass, (c) the maximum acceleration of the mass, (d) the total (mechanical) energy of the mass, (e) the period and frequency of the mass and spring and (e) the equation of the time dependent vertical position of the mass.

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Chapter13: Vibrations And Waves
Section: Chapter Questions
Problem 32P: A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is...
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1. A spring stretches 0.350 m when a 0.750 kg mass is hung from it. The spring is then stretched an
additional 0.250 m from this equilibrium point and released. Determine (a) the spring constant,
k, (b) the maximum velocity of the mass, (c) the maximum acceleration of the mass, (d) the total
(mechanical) energy of the mass, (e) the period and frequency of the mass and spring and (e)
the equation of the time dependent vertical position of the mass.
Transcribed Image Text:1. A spring stretches 0.350 m when a 0.750 kg mass is hung from it. The spring is then stretched an additional 0.250 m from this equilibrium point and released. Determine (a) the spring constant, k, (b) the maximum velocity of the mass, (c) the maximum acceleration of the mass, (d) the total (mechanical) energy of the mass, (e) the period and frequency of the mass and spring and (e) the equation of the time dependent vertical position of the mass.
Expert Solution
Step 1

Given that

          The mass hung from the spring (m) = 0.750Kg

          it is stretches (xo) = 0.350m

the amplitude of the system is

           A = 0.250m

The spring constant is given by

          mg = kxok = mgxo

Putting all the given values in the above equation , we get

           k = 0.75×100.35k = 21.42N/m

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