1. Calculate the total volume of 25 mM NaCitrate, and 25 mM NaPhosphate you will need for both day 1 and day 2. Total volume of 25 mM NaCitrate 940μl +945μl = 1885μl Total volume of 25 mM NaPhosphate 20μl + 15μl = 35 μl

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter33: Automated Methods Of Analysis
Section: Chapter Questions
Problem 33.8QAP
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1. Calculate the total volume of 25 mM NaCitrate, and 25 mM NaPhosphate you
will need for both day 1 and day 2.
Total volume of 25 mM NaCitrate 940μl +945μl = 1885μl
Total volume of 25 mM NaPhosphate 20μl + 15μl = 35 μl
2. Below provide the calculations necessary to produce those solutions from the
stock reagents provided. Below are the instructions to make 200mL of 25mM
NaCitrate with 0.1%BSA. NOTE: you do not need to make 200mL. Your volume
from problem 1 will be different. Finally, for the Na Phosphate buffer the MW is
141.96 g/mol.
25mM NaCitrate pH=4.8, containing 0.1% BSA (200ml)
MW= 294.10 g/mol
1.4705 grams into 190mL water add 0.2 grams BSA
. pH to 4.8 using dilute NaOH or HCI
Dilute to 200ml
I
●
Transcribed Image Text:1. Calculate the total volume of 25 mM NaCitrate, and 25 mM NaPhosphate you will need for both day 1 and day 2. Total volume of 25 mM NaCitrate 940μl +945μl = 1885μl Total volume of 25 mM NaPhosphate 20μl + 15μl = 35 μl 2. Below provide the calculations necessary to produce those solutions from the stock reagents provided. Below are the instructions to make 200mL of 25mM NaCitrate with 0.1%BSA. NOTE: you do not need to make 200mL. Your volume from problem 1 will be different. Finally, for the Na Phosphate buffer the MW is 141.96 g/mol. 25mM NaCitrate pH=4.8, containing 0.1% BSA (200ml) MW= 294.10 g/mol 1.4705 grams into 190mL water add 0.2 grams BSA . pH to 4.8 using dilute NaOH or HCI Dilute to 200ml I ●
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