1. Consider the titration of 25.0 mL of a weak acid, 0.100 M HCOOH (Ka = 1.8 x 10- 4) with 0.100M NAOH. NaOH (aq) + HCOOH(aq) →H20(1) + NaCHO2(aq) (i) %3D What is the pH of the solution after adding 5.00 mL of NaOH? After adding 12.5 mL 2 Veq = midpoint pH = pKa = 3.74 (ii)

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section: Chapter Questions
Problem 116SCQ: Two acids, each approximately 0.01 M in concentration, are titrated separately with a strong base....
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1. Consider the titration of 25.0 mL of a weak acid, 0.100 M HCOOH (Ka = 1.8 x 10-
4) with 0.100 M NaOH.
NaOH (aq) + HCOOH(aq) →H2O(1) + NaCHO2(aq)
(i)
What is the pH of the solution after adding 5.00 mL of NAOH?
(ii)
After adding 12.5 mL
2 Veq= midpoint pH = pKa = 3.74
Transcribed Image Text:1. Consider the titration of 25.0 mL of a weak acid, 0.100 M HCOOH (Ka = 1.8 x 10- 4) with 0.100 M NaOH. NaOH (aq) + HCOOH(aq) →H2O(1) + NaCHO2(aq) (i) What is the pH of the solution after adding 5.00 mL of NAOH? (ii) After adding 12.5 mL 2 Veq= midpoint pH = pKa = 3.74
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