The molecule CO2 reacts with H2O (L) and form H2CO3 according to the equation. CO2 (aq) + H20 (L) H2CO3 (aq) with an equilibrium constant of 2.0x10^-4 In addition, H2CO3 dissociate in water to form H+ions and HCO3-with an equilibrium constant of 4.3 x10^-7, according to the chemical reaction: H2CO3 (aq) H+ (aq) + HCO3- (aq) 1) Calculate the equilibrium constant for the reaction. H+ (aq) + HCO3- (aq) H20 (L) + CO2 (aq) 2) If the initial concentration of CO2 (aq) is 0.150 M. Calculate the equilibrium concentrations H+ ions, HCO3- ions, CO2 and H2CO
The molecule CO2 reacts with H2O (L) and form H2CO3 according to the equation. CO2 (aq) + H20 (L) H2CO3 (aq) with an equilibrium constant of 2.0x10^-4 In addition, H2CO3 dissociate in water to form H+ions and HCO3-with an equilibrium constant of 4.3 x10^-7, according to the chemical reaction: H2CO3 (aq) H+ (aq) + HCO3- (aq) 1) Calculate the equilibrium constant for the reaction. H+ (aq) + HCO3- (aq) H20 (L) + CO2 (aq) 2) If the initial concentration of CO2 (aq) is 0.150 M. Calculate the equilibrium concentrations H+ ions, HCO3- ions, CO2 and H2CO
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.41PAE: Because calcium carbonate is a sink for CO32- in a lake, the student in Exercise 12.39 decides to go...
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The molecule CO2 reacts with H2O (L) and form H2CO3 according to the equation.
CO2 (aq) + H20 (L) H2CO3 (aq) with an equilibrium constant of 2.0x10^-4
In addition, H2CO3 dissociate in water to form H+ions and HCO3-with an equilibrium constant of 4.3 x10^-7, according
to the chemical reaction :
H2CO3 (aq) H+ (aq) + HCO3- (aq)
1) Calculate the equilibrium constant for the reaction.
H+ (aq) + HCO3- (aq) H20 (L) + CO2 (aq)
2) If the initial concentration of CO2 (aq) is 0.150 M. Calculate the equilibrium concentrations H+ ions, HCO3- ions, CO2 and H2CO3 at equilibrium.
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