1. Cu(s) | Cu2+ (0.05 M) || Cu2+ (1 M) | Cu(s) 0.039 v Calculation for E (cal.) (eq. 11): EO-0.0592 n Ta 0.0592 E = F a) What happens to the concentration of the 0.05 M solution as the reaction proceeds? b) What happens to the concentration of the 1 M solution as the reaction proceeds? c) What has happened to the concentrations of both solutions when the emf reaches 0 V?

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
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Chapter22: Bulk Electrolysis: Electrogravimetry And Coulometry
Section: Chapter Questions
Problem 22.33QAP
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1b

1. Cu(s) | Cu2+ (0.05 M) || Cu2+ (1 M) | Cu(s)
0.039 v
Calculation for E (cal.) (eq. 11):
EO-0.0592 n
Ta
0.0592
E = F
a) What happens to the concentration of the 0.05 M solution as the reaction
proceeds?
b) What happens to the concentration of the 1 M solution as the reaction proceeds?
c) What has happened to the concentrations of both solutions when the emf
reaches 0 V?
Transcribed Image Text:1. Cu(s) | Cu2+ (0.05 M) || Cu2+ (1 M) | Cu(s) 0.039 v Calculation for E (cal.) (eq. 11): EO-0.0592 n Ta 0.0592 E = F a) What happens to the concentration of the 0.05 M solution as the reaction proceeds? b) What happens to the concentration of the 1 M solution as the reaction proceeds? c) What has happened to the concentrations of both solutions when the emf reaches 0 V?
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