1. For the half-wave rectifier circuit of Figure 2–1A, the peak load voltage is approximately :(a) 6 V ¯.. 2. For an input frequency of 60 Hz, the period of the half-wave signal is approximately (a) 4 ms 3. Compared to the de output voltage of the half-wave rectifier of Figure 2-1A, the de output voltage of the full-wave bridge rectifier of Figure 2-1C is approximately (a) one-half as large 4. In this experiment, the rectifier circuit that has the lowest diode peak inverse voltage is the (a) half-wave rectifier (c) full-wave bridge rectifier (d) both a and c 5. In this experiment, the rectifier circuit that has the greatest de output voltage is the (a) half-wave rectifier (c) full-wave bridge rectifier (b) 12 V (c) 18 V - (d) 24 V (b) 8 ms (c) 16 ms (d) 32 ms (b) the same (c) twice as large ( ) (b) full-wave center-tapped rectifier ( ) (b) full-wave center-tapped rectifier TUIC ALL C ICUD r vO INEE D.

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 4RQ: What is the difference between a diode and rectifier?
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1. For the half-wave rectifier circuit of Figure 2–1A, the peak load voltage is
approximately
(а) 6 V "..
2. For an input frequency of 60 Hz, the period of the half-wave signal
is approximately
(а) 4 ms
3. Compared to the de output voltage of the half-wave rectifier of Figure
2-1A, the dc output voltage of the full-wave bridge rectifier of Figure
2-1C is approximately
(a) one-half as large
4. In this experiment, the rectifier circuit that has the lowest diode peak
inverse voltage is the
(a) half-wave rectifier
(c) full-wave bridge rectifier (d) both a and c
5. In this experiment, the rectifier circuit that has the greatest de output
voltage is the
(a) half-wave rectifier
(c) full-wave bridge rectifier
(b) 12 V
(c) 18 V -
(d) 24 V
()
(b) 8 ms
(c) 16 ms
(d) 32 ms
(b) the same
(c) twice as large
(b) full-wave center-tapped rectifier
(b) full-wave center-tapped rectifier
( )
THIS ALL FIGURE YOU NEED:
IN4001
C.T
v, peak)V, (peak) >
120 VAC
I kN
60 Hz
12.6
VAC
А.
IN4001
V, (peak).
.T.
12.6=
VAC
120 VAC
V. (peak)1 kN
60 Hz
IN4001
в.
C.T v, (peakà
İN4001
(4)
V, (peak)21 kN
120 VAC
12.6
VAC
60 Hz
С.
FIGURE 2–1
Schematic diagram of circuits.
Transcribed Image Text:1. For the half-wave rectifier circuit of Figure 2–1A, the peak load voltage is approximately (а) 6 V ".. 2. For an input frequency of 60 Hz, the period of the half-wave signal is approximately (а) 4 ms 3. Compared to the de output voltage of the half-wave rectifier of Figure 2-1A, the dc output voltage of the full-wave bridge rectifier of Figure 2-1C is approximately (a) one-half as large 4. In this experiment, the rectifier circuit that has the lowest diode peak inverse voltage is the (a) half-wave rectifier (c) full-wave bridge rectifier (d) both a and c 5. In this experiment, the rectifier circuit that has the greatest de output voltage is the (a) half-wave rectifier (c) full-wave bridge rectifier (b) 12 V (c) 18 V - (d) 24 V () (b) 8 ms (c) 16 ms (d) 32 ms (b) the same (c) twice as large (b) full-wave center-tapped rectifier (b) full-wave center-tapped rectifier ( ) THIS ALL FIGURE YOU NEED: IN4001 C.T v, peak)V, (peak) > 120 VAC I kN 60 Hz 12.6 VAC А. IN4001 V, (peak). .T. 12.6= VAC 120 VAC V. (peak)1 kN 60 Hz IN4001 в. C.T v, (peakà İN4001 (4) V, (peak)21 kN 120 VAC 12.6 VAC 60 Hz С. FIGURE 2–1 Schematic diagram of circuits.
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