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- Which EWMA chart below will yield ARL performance most close to that of cusum chart with k=1/2 and h=5? a. L=2.814, lamda=0.10 b. L=2.615, lamda=0.05 c. L=2.998, lamda=0.25 d. L=3.054, lamda=0.40 e. L=2.962, lamda=0.20From September 1980 to August 1982, 50 premature infants were admitted to the Neonatal ICU of Lungsod ng Kabataan Children’s Hospital due to severe hyaline membrane disease. Data on the weights of these infants are shown below. Table X. Weights of Premature Infants with Severe Hyaline Membrane Disease Treated with Assisted Ventilation Weights in Grams Number of Patients 800-1000 1001-1200 1201-1400 1401-1600 1601-1800 1801-2000 2001-2200 2201-2400 3 4 6 5 5 8 9 10 Total 50 Find the following: Final Answer Interpretation Computation Mean Median Mode Range SD D6 P40 Q3At a meeting of information systems for regional offices of a national company, a survey was taken to determine the number of employees the officers supervise in the operation of their departments, where X is the number of employees overseen by each information systems officer. Table X_____________________ Frequency 1 _____________________7 2 _____________________5 3 _____________________11 4 _____________________8 5 _____________________9 Referring to the Table above, how many regional officers are represented in the survey results?
- Two analysts were given a standard reference material (SRM) and were asked to determine its copper concentration (in mg/kg) using the EPA standard method. Each analyst was given sufficient time so they could produce as many accurate results as possible. Their results (mg/kg) were as follows: Analyst A 45.2, 47.3, 51.2, 50.4, 52.2, 48.7 (Standard error s = 2.62) Analyst B 49.4, 50.3, 51.6, 52.1, 50.9 (Standard error s = 1.06) (a) For Analyst A, is 52.2 mg/kg a possible outlier? (b) Calculate the RSD for each student; which analyst is more precise? (c) If the known concentration of copper in SRM is 49.5 mg/kg, which analyst is more accurate (without considering the deletion of outliers if any)?A farmer would like to investigate the relationship between the obtained yield of apple trees and the amount of weeds found in their roots. For this reason, nine apple trees of the same type were randomly selected and the amount of weeds in their roots (x grams) was recorded together with their yield (y kilograms). Year #1 #2 #3 #4 #5 #6 #7 #8 #9 #10 Weeds in roots (x) 30 28 32 25 25 24 22 24 35 40 Yield (y) 25 30 27 40 42 41 50 45 30 25 Draw a scatter diagram of these data. Label the diagram carefully. Calculate the sample correlation coefficient. Interpret your findings. Calculate the least squares line of y on x and draw the line on the scatter diagram. Based on the regression equation in part (iii.), what will be the predicted yield of apple for a tree with 37 grams of weeds in its roots? Will you trust this value? Justify your answer. Briefly comment on…Healthy men aged 21 to 35 were randomly assigned to one of two groups: half received 0.82 grams of alcohol per kilogram of body weight; half received a placebo. Participants were then given 30 minutes to read up to 34 pages of Tolstoy’s War and Peace (beginning at chapter 1, with each page containing approximately 22 lines of text). Every two to four minutes participants were prompted to indicate whether they were “zoning out.” The proportion of times participants indicated they were zoning out was recorded for each subject. The table below summarizes data on the proportion of episodes of zoning out (a) What are the two sample standard deviations? (b) What degrees of freedom does the conservative Option 2 use for two-sample t procedures for these samples? (c) Using Option 2, give a 90% confidence interval for the mean difference between the two groups.
- Consider the following temperature readings (measured in Celsius scale) of few days in Dhaka city during lastmonth" 29, 25, 26, 30, 33, 21, 27, 28. Calculate Skewness and interpret this measure. 1. Calculate Skewness and interpret this measure. A. - 0.105; skewed to the righ B. 0.105; skewed to the rightC. - 0.105; skewed to the leftD. 0.105; skewed to the leftThe article “Snow Cover and TemperatureRelationships in North America and Eurasia” (J.Climate and Applied Meteorology, 1983: 460–469) usedstatistical techniques to relate the amount of snow coveron each continent to average continental temperature.Data presented there included the following ten observationson October snow cover for Eurasia during the years1970–1979 (in million km2):6.5 12.0 14.9 10.0 10.7 7.9 21.9 12.5 14.5 9.2What would you report as a representative, or typical,value of October snow cover for this period, and whatprompted your choice?Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives it until it runs out of gas. He conducts this experiment 15 times on each car and records the number of miles driven. Full data set Car 1 216 243 205 242 239 297 295 172 270 251 165 310 265 316 278 Car 2 231 220 223 205 245 257 242 292 248 252 287 255 250 293 251 Median for Car 2 M=___________mi / 10 gal (Type an integer or decimal rounded to one decimal place as needed.) Range for Car 1 R=__________mi / 10 gal (Type an integer or decimal rounded to one decimal place as needed.) Range for Car 2 R=__________mi / 10 gal (Type an integer or decimal rounded to one decimal place as needed.) Sample standard deviation for Car 1 s=_________mi / 10 gal (Type an integer or decimal rounded to one decimal place as needed.) Sample standard deviation…
- Periodically, the county Water Department tests the drinking water of homeowners for contaminants such as lead and copper. The lead and copper levels in water specimens collected in 1998 for a sample of 10 residents of a subdevelopement of the county are shown below. lead (μμg/L) copper (mg/L) 4.4 0.643 2.4 0.57 1.5 0.46 2.6 0.895 5.9 0.2 3.4 0.54 3.8 0.245 1.6 0.583 5.7 0.769 1.7 0.215 (a) Construct a 9999% confidence interval for the mean lead level in water specimans of the subdevelopment. ≤μ≤The Prevalence per 10,000 population of having health insurance for 1 (Table 5 box s. above) is: The Prevalence per 10,000 population of having health insurance for 2 (Table 5 box w. above) is:It is considered quite common to have feet of unequal length. In a sample of 10 healthy college students the right-foot and left-foot lengths are given (in mm). Length in mm mean ss Left foot (xx) 268 274 258 259 256 256 264 263 269 270 263.7 6.3779132776932 Right foot (yy) 247 281 249 259 231 273 267 264 285 265 262.1 16.3737594949969 d=x−yd=x−y 21 -7 9 0 25 -17 -3 -1 -16 5 1.6 13.9459273226591 (a) Find the test statistic. (b) Test the claim at the 0.05 significance level. Positive critical value: Negative critical value: Is there sufficient data to support the claim?YesNo