1. Subtract [4-4-2] - [4 –3 5]. O A. [0 –7 3] O B. [0 –1 7] O C. [0 -1-7] O D. [0 -1 3] V Mark for review (Will be highighted on the review page) Next Question >>
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![1. Subtract [4-4-2] - [4 –3 5].
O A. [0 -7 3]
O B. [0 –1 7]
O C. [0 –1-7]
O D. [0 –1 3]
V Mark for review (Will be highlighted on the review page)
Next Question >>
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#3
2 Y
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4 8
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- lst = [10, 20, 30, 40, 50, 60, 70, 80] def f(lst, seek): for i in range(len(lst)): if lst[i] == seek: return i # Return position immediately return None f(lst,50) What is the output of this code part? A)3 B)4 C)5 D)none9.3.1: Output values below an amount. Write a program that first gets a list of 5 integers from input. Then, get another value from the input, and output all integers less than or equal to that value. Ex: If the input is 50 60 140 200 75 100, the output is: 50 60 75 For coding simplicity, follow every output value by a space, including the last one. Then, output a newline. Such functionality is common on sites like Amazon, where a user can filter results. Codes need to be writing in coral languageA palindrome is a word or phrase that is identical when you read from forward or backward, such as the words “racecar” and “madam.” A standard palindrome is similar to a perfect palindrome, except that spaces and punctuation are ignored in a standard palindrome. For example, “Madam, I’m Adam” is a standard palindrome because the characters are identical forward or backward, provided you remove the spaces and punctuation marks. Write a PHP script that checks words or phrases stored in two separate string variables to determine if they are a perfect palindrome. In addition, see if you can modify the program to check for standard palindromes. create a web page with a text field and “Reset” and “Submit” buttons. When a user clicks on the submit button, show the standard and perfect palindromes of the string that was entered in the text field on the same page.
- A palindrome is a word or phrase that is identical when you read from forward or backward, such as the words “racecar” and “madam.” A standard palindrome is similar to a perfect palindrome, except that spaces and punctuation are ignored in a standard palindrome. For example, “Madam, I’m Adam” is a standard palindrome because the characters are identical forward or backward, provided you remove the spaces and punctuation marks. Write a PHP script that checks words or phrases stored in two separate string variables to determine if they are a perfect palindrome. In addition, see if you can modify the program to check for standard palindromes. create a web page with a text field and “Reset” and “Submit” buttons. When a user clicks on the submit button, show the standard and perfect palindromes of the string that was entered in the text field on the same page. Create a separate Index.html and php filedictionaries = [] dictionaries.append({"First":"Bob", "Last":"Jones"}) dictionaries.append({"First":"Harpreet", "Last":"Kaur"}) dictionaries.append({"First":"Mohamad", "Last":"Argani"}) for i in range(0, len(dictionaries)): # Condition that's print the full name when Condition is True if(dictionaries[i]['First']=='Bob')or(dictionaries[i]['Last']=='Kaur'): print(dictionaries[i]['First']+" "+dictionaries[i]['Last']) ********************************** please modify the code to use a while loop instead of a for loop#include <iostream> using namespace std; int main() { string c_name ; string car_n; int n, member_n , total ,d; char choice; cout<< "Muscat Auto Workshop"<<endl<<endl; cout<< "Enter customer name : ";cin>>c_name; cout<<" Enter car plate number : ";cin>>car_n; cout<<" choice the required service "<<endl; cout<<" 1-Basic Tuning : 50 OMR "<<endl; cout<<" 2-Software Re-installation : 60 OMR "<<endl; cout<<" 3-Parts Replacement : 100 OMR"<<endl; cout<<" 4-Body Paint : 120 OMR"<<endl; cin>>n; if(n==1) { cout<<" charges before discout = 50 OMR "<<endl; } else if ( n==2) { cout <<" charges before discount = 60 OMR "<<endl; }else if (n==3) { cout<<" charges before discount = 100 OMR "<<endl; }else if (n==4 ) { cout<<" charges before discount = 120 OMR"<<endl; } cout<<" Do you…
- c++ problem. Please paste ur indented code.Which of the following statement(s) are true for the above code? Group of answer choices the code allocates space for a local variable and a global array the code allocates space for a local variable and a local array The code utilizes the index register the code utilizes the stack pointer the code uses 5 different addressing modes2 - Create a procedure that generates a random string of length L, containing all capital letters. You’ll request from the user the length L by displaying a prompt message, and at the end display an output message containing the random string. You should replace the call for WriteString for WriteStringAnimated, and as always remember to restore the register values when returning to the main procedure. You can expect your code to look like this: include Irvine32.inc .386 .model flat,stdcall .stack 4096 ExitProcess PROTO, dwExitCode:DWORD .data promptForTheSize BYTE "Enter the size of the string: ", 0 outputMessage BYTE "The random string is: ", 0 .code main PROC call RandomString call Crlf call WaitMsg INVOKE ExitProcess,0 main ENDP WriteStringAnimated PROC ; Complete the implementation for this procedure WriteStringAnimated ENDP RandomString PROC ; Complete the implementation for this procedure RandomString ENDP END main ------------------------------------- Feel free to modify the…
- What will the following code display?numbers = [1, 2, 3, 4, 5]numbers[2] = 99print(numbers)C++ Help Please! Complete the code provided to add the appropriate amount to totalDeposit. #include <iostream>using namespace std; int main() { enum AcceptedCoins {ADD_QUARTER, ADD_DIME, ADD_NICKEL, ADD_UNKNOWN}; int totalDeposit = 0; int userInput; totalDeposit = 0; cout << "Add coin: 0 (add 25), 1 (add 10), 2 (add 5). "; cin >> userInput; if (userInput == ADD_QUARTER) { totalDeposit = totalDeposit + 25; } /* Your solution goes here */ else { cout << "Invalid coin selection." << endl; } cout << "totalDeposit: " << totalDeposit << endl; return 0;}int_to_bytes_big_endian(num): bytestr=deque() whilenum>0: # list.insert(0, ...) is inefficient bytestr.appendleft(num&0xff) num >>= 8 returnbytes(bytestr) def int_to_bytes_little_endian(num): bytestr= [] whilenum>0: bytestr.append(num&0xff) num >>= 8 returnbytes(bytestr) def bytes_big_endian_to_int(bytestr): num=0 forbinbytestr: num <<= 8 num+=b returnnum def bytes_little_endian_to_int(bytestr): num=0.