1. The alternate form of a gene is A. Alternate type B. Recessive character C. Dominant character D. Allele 1. The alternate form of a gene isA. Alternate typeB. Recessive characterC Dominant characterD. Allele2. DNA was extracted from cells of Staphylococcus and found to have 37% cytosine. What percent ofguanine does this species have?A. 37%B. 13%C. 74%D. 26%3. Nucleotide is the building block of DNAa. Trueb. False4. The structures within living cells that contain the genetic material is calledA. ChromosomeB. NucleosomeC RibosomeD. Nucleolus5. The branch of genetics that studies the genetic variation within and between local populations of aspecies is calledA. Population geneticsB. Molecular geneticsC. lassical geneticsD. Cytogenetics6. The basic functional and structural unit of heredity isA GeneB. NucleotideC. PhosphateD. Nitrogen

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Description: 1. The alternate form of a gene is A. Alternate type B. Recessive character C. Dominant character D. Allele 1. The alternate form of a gene isA. Alternate typeB. Recessive characterC Dominant characterD. Allele2. DNA was extracted from cells of Staph

Genes are DNA sequences of nucleotides that code for RNA, which in turn codes for a protein. In the…

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1. The alternate form of a gene is A. Alternate type B. Recessive character C. Dominant character D. Allele

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 6SQ: Choose the statement that is incorrect. a. A son can inherit a recessive allele on an X chromosome...

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Variation in _____ is the basis of variation in traits. a. karyotype b. the DNA sequence c. the double helix d. chromosome number
Choose the statement that is incorrect. a. A son can inherit a recessive allele on an X chromosome from either parent. b. An individual may inherit three or more of each type of chromosome characteristic or the species, a condition called polyploidy. c. A female child inherits one X chromosome from her mother and one from her father. d. Pedigree analysis can be used to determine a future childs chance of being born with achcondroplasia.
4. Marfan syndrome is a genetic trait caused by in a dominant allele. The trait causes a weakening of the aorta that can be fatal. A teenager whose mother has the syndrome (but whose maternal grandfather was not affected), and whose father was unaffected, is concerend that she may have the trait. a. What is the phenotype of each of her parents? Genotype? b. What is the chance that the teenager has Marfan syndrome?
1. The frequency of a recessive disease is 9%. What is the frequency of the allele that causes s the disease? a) What is the frequency of the dominant allele? b) What is the frequency of the carriers (heterozygotes) of the disease?
9)If a gene shows classic dominance (one allele is dominant, one is allele is recessive), what is the phenotype of a heterozygote? a)Recessive phenotype b)Unable to determine without more information c)Dominant phenotype d)Mixed phenotype
4. Define the following terms: A. genotype B. phenotype C. monohybrid D. dihybrid
1. a) If you were at risk of a fatal disease such as Huntington’s disease and only the 95% accurate preliminary genetic test was available, would you take the test? After all, 95% of the time the test would tell you whether you would eventually get Huntington’s disease or whether you did not have to worry about getting this disease. b) The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?
4.Eyelash length is an inherited trait. In the human population, there is an eyelash length gene. There are two possible variants of this gene—an allele for long eyelashes (> 1cm) and an allele for short eyelashes (1 cm or less). The allele for long eyelashes is dominant (L) and the allele for short eyelashes is recessive (l). An individual who is heterozygous for eyelash length would have which of the following genotypes? A.Short eyelashes B.Ll C.LL D.Long eyelashes
1.What would you predict would happen if you added Anti-A serum to this type of blood? 2. What would you predict would happen if you added Anti-B serum to this type of blood?3. Why is the genotype that codes for this blood type considered “codominant”?Please answer all of them now and do it
You are a studying the genetic basis of horn color in unicorns. Gene C determines the color of pigment destined for the horn by converting a pink precursor into a purple pigment. C- individuals make purple pigment whereas cc individuals accumulate pink precursor. Gene D ensures the deposition of the pigment into the horn cells, such that D- individuals have a colored horn (purple or pink), whereas dd individuals have a white horn. You breed two purple horned unicorns to each other (CcDd). Assuming Gene C and Gene D are unlinked, what is the probability that the baby unicorn has a purple horn? Please express your answer to 2 decimal places (e.g. 0.69).
7)Homozygote is a)an individual who has two copies of the same allele for a particular gene b)an individual who has to different alleles for a particular gene c)an individual who has one copy of the most common allele for a particular gene d)an individual who has one copy of the least common allele for a particular gene
1. The first genetic test used a short DNA sequence that was closely linked to the Huntington’s locus. People taking the test were classified as to whether they had the DNA sequence that was linked to the Huntington’s disease. This method was 95% accurate. This means that 95% of the people who had the Huntington’s-linked DNA sequence actually inherited the Huntington allele. It also meant that 95% of the people who did not have the DNA sequence linked to the Huntington allele did not inherited the wild-type allele (not the Huntington allele).Why might this preliminary test not be as accurate as a gene test for the actual Huntington’s allele? Explain.