1. The table shows pressure at different depths of waterPressure (poundDepth (feet)per square inch)14.70019.031023.36203027.694032.025036.356040.68a) Without graphing the data, tell if this graph follows a linear or anexponential pattern. Hint: Calculate first differences and percentagechanges and see which is more constant.b) Find an equation to model the pressure of the water.c) If the model is linear, write a sentence of interpretation for the slope and ifit's exponential, find the constant percentage change for the modelequation

Question
Asked Sep 9, 2019
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1. The table shows pressure at different depths of water
Pressure (pound
Depth (feet)
per square inch)
14.70
0
19.03
10
23.36
20
30
27.69
40
32.02
50
36.35
60
40.68
a) Without graphing the data, tell if this graph follows a linear or an
exponential pattern. Hint: Calculate first differences and percentage
changes and see which is more constant.
b) Find an equation to model the pressure of the water.
c) If the model is linear, write a sentence of interpretation for the slope and if
it's exponential, find the constant percentage change for the model
equation
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1. The table shows pressure at different depths of water Pressure (pound Depth (feet) per square inch) 14.70 0 19.03 10 23.36 20 30 27.69 40 32.02 50 36.35 60 40.68 a) Without graphing the data, tell if this graph follows a linear or an exponential pattern. Hint: Calculate first differences and percentage changes and see which is more constant. b) Find an equation to model the pressure of the water. c) If the model is linear, write a sentence of interpretation for the slope and if it's exponential, find the constant percentage change for the model equation

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Expert Answer

Step 1

Given information:

The table shows pressure at different depths of water:

 

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Depth (feet) Pressure (pound per square inch) 14.70 0 10 19.03 23.36 20 30 27.69 40 32.02 50 36.35 60 40.68

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Step 2

Calculation:

First difference is calculated by f(x+h)-f(x).

 

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f(10)-f(0) 19.03-14.70 =4.33

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Step 3

Second Difference is calculated ...

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f(20)-f(10)23.36-19.03 -4.33

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