1. Two people with wavy hair have a straight-haired child. Wavy hair is a dominant. What are the genotypes of the parents? What is the possibility that their next child will have wavy hair? Show the genotype and phenotype ratios that result from the above cross. Show the Punnett square.
1. Two people with wavy hair have a straight-haired child.
- Wavy hair is a dominant.
- What are the genotypes of the parents?
- What is the possibility that their next child will have wavy hair?
- Show the genotype and
phenotype ratios that result from the above cross. Show the Punnett square.
According to the premise of the question wavy hair is dominant over straight hair. Since, the child have straight hair it indicates that both the parents are heterozygous for wavy hair trait because if one of the parent is homozygous for wavy hair gene all the offsprings will have wavy hair. Let's assume that wavy hair gene is denoted by-''W'' and straight hair gene is denoted by-''w'' then the genotype of both the parents would be ''Ww'' and the genotype of the straight hair child would be ''ww". This is in accordance with Mendel's law of segregation which states that:- alleles segregate randomly into gametes : when gametes are formed, each allele of one parent segregates randomly into the gametes, such that half of the parent's gametes carry each allele.
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