1.5 kN 120 mm Outer diameter: 72 mm Inner diameter: 62 mm 150 mm 120 mm 4.5 kN A For element A find: (a) Torsional shearing stress (b) Transverse shear stress (c) Normal stress Q = [AS] x y 2rm y = TT

1.5 kN 120 mm Outer diameter: 72 mm Inner diameter: 62 mm 150 mm 120 mm 4.5 kN A For element A find: (a) Torsional shearing stress (b) Transverse shear stress (c) Normal stress Q = [AS] x y 2rm y = TT

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.2.4P: .4 The stresses on an clement arc known to be sx= 120 MPa, sy= 100 MPa, and txy= 75 MPa. Find the...

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

1.5 kN
120 mm
Outer diameter: 72 mm
Inner diameter: 62 mm
150 mm
D
120 mm
4.5 kN
A
For element A find:
(a) Torsional shearing stress
(b) Transverse shear stress
(c) Normal stress
Q = [AS] × y
2rm
TU
y =

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Step 1: Evaluate the equivalent force couple system along the axis of hollow circular shaft at free end.

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Step 2: Represent the equivalent force couple system in 2D representation (that is in yz - plane).

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Step 3: a) Evaluate torsional shear stress.

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Step 4: b) Evaluate transverse shear stress.

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Step 5: c) Evaluate normal stress due to bending moments.

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