10 10 20 22 25 27 How many internal nodes will there be after we delete 10?
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- (java)create a generic node class. create another class called op, that contains methods to add or delete nodes in any location.COVID-19 has effected whole world. People are interested in knowing current situation of COVID-19. You are required to write JAVA program for storing information in a Single way Linked List. Following JAVA classes are provided. // Node class public class COVIDDetail { public String country; public int activecases; public COVIDDetail next; } // linked List class public class COVIDList { COVIDDetail start=null; } You are required to add following methods to COVIDList class 1.void add(COVIDDetail n) this method receives a node as argument and adds it to given list. Nodes are arranged in descending order with respect to number of cases. Note that you are not required to sort the list in fact while adding first find its appropriate position and then add given node to that position. 2.void updateCases(String country_name , int cases) this method receives two arguments country name and cases (can have positive or negative value). Update active cases of those countries whose name…1) Which of the following statements are true about Linked Lists. a) Linked Lists use exactly as much memory as is needed for for all nodes. b) Linked Lists always have a head reference c) Linked Lists can grow dynamically d) None of these answers. e) Linked Lists are efficient when you need random access. 2) What is the average Big O runtime of retrieving a value of an item in a link list given its index? a) O(n) b) O(1) c) O(n^2) d) None of these answers. e) O(nlogn) 3) When does the insert() function of a Dynamic List have a big O runtime of O(1)? a) When you are inserting to the end of the list. b) When you are inserting to the beginning of the list. c) When the size of the data is small. d) None of these answers. 4) Why does retrieving a value from an array have a runtime of O(1)? (Select all that reasons that make this possible.) a) Arrays use simple math calculations to compute the requested index location. b) Arrays have to search…
- The programming language is Python Instructions: Create a function that will delete a node in a Linked List based on position number. On below example, if you want to delete position #2, it will remove the Banana (arrangement of nodes below is Apple, Banana, Cherry, Grapes, Orange). myLinkedList = LinkedList() myLinkedList.append("Banana") myLinkedList.append("Cherry") myLinkedList.append("Grapes") myLinkedList.append("Orange") myLinkedList.prepend("Apple") myLinkedList.deleteByPositionNum(2) node = myLinkedList.head while node: print(node.value, " ") node = node.next_node You may start with the function head:def deleteByPositionNum(self, positionNum):int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodesA skip listThe second programming homework is already on a server (http://marmoset.famnit.upr.si).In this task, a skip list data structure should be implemented. You can follow the followinginstructions:- Implement the class NodeSkipList with two components, namely key node and arrayof successors. You can also add a constructor, but you do not need to add anymethod.- In the class SkipList implement a constructor SkipList(long maxNodes). The parameter maxNodes determines the maximal number of nodes that can be added to askip list. Using this parameter we can determine the maximal height of a node, thatis, the maximal length of the array of successors. As the maximal height of a nodeit is usually taken the logarithm of the parameter. Further, it is useful to constructboth sentinels of maximal height.- In the class SkipList it is useful to write a method which simulates coin flip andreturns the number of all tosses until the first head comes up. This number representsthe height of a node…
- I.2. Which statement is false?a) Linked lists are collections of data items "lined up in a row," insertions and deletions can be madeanywhere in a linked list.b) Insertions and deletions are made only at one end of a stack, its top. c) Insertions and deletions are made only at one end of a queue, its tail. d) Binary trees facilitate high-speed searching and sorting of dataFill a linked list with five million random values. Traverse the entire list (not print) using Iterator with .next() get(4999999) Measure the elapsed time for each approach using System.nanoTime(). Report the results.single dounle linked list update a target node with a given key. i)Define a addAfter method to insert a new node after a given key (call seach())j) Define a addbefore method to insert a new node before a given key (call seach())k) Define a removeAt method to remove a node for a given key (call seach())
- My code does not produce the required output, can anyone let me know what seems to be off? Input: from Node import Node from LinkedList import LinkedList def print_linkedlist(list): print(f'Linked List ------ Nodes ----------------------------------') print(f'head: {list.head.name:<6}', end=' ') node = list.head while node != None: print(f"{node.name:<12}", end=' ') node = node.next print() print(f'tail: {list.tail.name:<6}', end=' ') node = list.head while node != None: print(f"data:{node.data:<7}", end=' ') node = node.next print() print(f' ', end=' ') node = list.head while node != None: if node.next != None: print(f"next:{node.next.name:<7}", end=' ') else: print("next:None") node = node.next print() print(f' ', end=' ') node = list.tail while node != None: if node.prev != None:…My code does not produce the required output, can anyone let me know what seems to be off? Input: from Node import Node from LinkedList import LinkedList def print_linkedlist(list): print(f'Linked List ------ Nodes ----------------------------------') print(f'head: {list.head.name:<6}', end=' ') node = list.head while node != None: print(f"{node.name:<12}", end=' ') node = node.next print() print(f'tail: {list.tail.name:<6}', end=' ') node = list.head while node != None: print(f"data:{node.data:<7}", end=' ') node = node.next print() print(f' ', end=' ') node = list.head while node != None: if node.next != None: print(f"next:{node.next.name:<7}", end=' ') else: print("next:None") node = node.next print() print(f' ', end=' ') node = list.tail while node != None: if node.prev != None:…You have two numbers represented by a linked list, where each node contains a singledigit. The digits are stored in reverse order, such that the 1 's digit is at the head of the list. Write afunction that adds the two numbers and returns the sum as a linked list.EXAMPLEInput: (7-> 1 -> 6) + (5 -> 9 -> 2).That is,617 + 295.Output: 2 -> 1 -> 9. That is, 912.FOLLOW UPSuppose the digits are stored in forward order. Repeat the above problem.Input: (6 -> 1 -> 7) + (2 -> 9 -> 5).That is,617 + 295.Output: 9 -> 1 -> 2. That is, 912