10 Life insurance policies in a sample of 200 taken out of 50,000 were found to be insured for less than $5000. How many policies can be reasonably expected to be insured for less than $5000 in the whole lot at 95 per cent confidence level?

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Sample size:The minimum sample size for a desired confidence level, α with a given margin of error,…

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: Compute the margin of error of the 90% confidence level when a = 3 and n= 30

A: Given that  ?=3 , n=30 Formula for margin of error  E=Zc*?/√(n)

Q: In response to a recent GSS survey on whether the Government should impose strict laws to prohibit…

A: Solution: Let X be the number of subjects said “yes” and n be the sample number of subjects. From…

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: In a random sample of 100 voters in a school district, 40 of them stated they were in favor of the…

A: Solution: Let X be the number of voters stated they were in favor of the school district bond…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: If n = 200 and p^ = 0.64, find the margin of error at a 95% confidence level.

A:

Q: 1. A consumer watch group interviewed a random sample of 1000 consumers and asked them if they are…

A: Here use confidence interval for population proportion

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: If n=160 and ˆp (p-hat) =0.48, find the margin of error at a 99% confidence level

A: Given Data: p^=0.48n=160   We know that, p^-pp^(1-p^)n~ Normal(0,1)

Q: n a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: The given data is appropriate for single proportion confidence interval . because it is a large…

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

A:

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: According to the provided information, The z score at 95% confidence interval from the standard…

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: 5-Seventy percent of 50 randomly selected students from college of science and engineering were…

A:

Q: Explain which would result in a wider large-sample confidence interval for p: a sample size n=100 or…

A: The sample sizes are 100 and 400.

Q: In a poll of 1000 randomly selected voters in a local election, 473 voters were against fire…

A: Given,n=1000x=473α=1-0.99=0.01α2=0.005z0.005 =2.58

Q: In a poll of 1000 randomly selected voters in a local election, 497 voters were in favor of school…

A: Given information Sample size (n) = 1000 We have given that out of 1000 voters, 497 voters were in…

Q: In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education. Find…

A: Ans- Given the level of confidence interval   90 %                                        Then   α =…

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: n a recent poll, 500 people were asked if they liked dogs, and 92% said they did. Find the margin of…

A: Given data, n=500 p=92%=0.92 Z value at 90% confidence is Zc=1.645 margin of error(E)=?

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: The formula for the sample size is as follows:

Q: In June 2020, a Gallup Poll asked U.S. adults whether immigration was a good thing or a bad thing…

A: Given X=600 n=1000

Q: 2) In a sample of 32 Toyota Tundra trucks from around a city, 14 have satellite radio as part of the…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A:

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: 1. In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education.…

A:

Q: In a recent poll of 200 randomly selected adults in the U.S., 130 were registered to vote. a) What…

A: Hello, thanks for your question. Since you have posted a question with multiple sub-parts, we will…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Here, there is no information about the population parameter. Hence, use the conservative estimate…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: Suppose you are designing a survey of firework plans among Kansas residents. You would like for the…

A: Here we need to find the required sample size with a 95% confidence level to estimate the number of…

Q: 3: In a poll of 1000 likely voters, 560 say that the United States spends too little on fighting…

A:

Q: b. Construct a 90% confidence interval for the percentage of all judges who are in favor of the…

A: a. A random sample of 15 judges and asked them whether or not they favor the death penalty in which…

Q: university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: A college administrator is interested in determining the proportion of students who receive some…

A:

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: Construct a 99% confidence interval for the true proportion of all car license applications that…

A: Given Information:x=25n=155c=99%=0.99

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a…

A: The provided information is: It is given that 106 college students (s) own a car among 258 college…

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Sample size (n) = 439 240 of them said that they were struggling that is x = 240. The sample…

Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given, The sample proportion is,

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Given dataError = 2.5% = 0.025Confidence level = 0.995Significance level = α=1-0.995=0.005