10 mL of salt spirit sample was taken and volume of distilled water was added to the volume to 50 mL. completed. This solution was titrated with 0.1 M NaOH and 12 mL of NaOH was spent. Accordingly, calculate the amount of HCl in the spirit of salt as g / L. HCl + NaOH → NaCl + H2O

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A: Volume of NaoH =15 mL Volume of HCl=11.34 mL Molarity of HCl=0.1311M

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A:

Q: Solution-- 20.00 mL of HCL with 25.46 mL of NaOH NaOH is 0.1240 M

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Q: solution

A: Dear student I have given answer to your question in the image format.

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.