10. Find the 95% confidence interv al ol ue uereice an means in Exercise 6 of this section. 11. Hours Spent Watching Television According to Nielsen Media Research, children (ages 2-11) spend an average of 21 hours 30 minutes watching television per week while teens (ages 12-17) spend an average of 20 hours 40 minutes. Based on the sample statis- tics shown, is there sufficient evidence to conclude a se at 9-19 498 Chapter 9 Testing the Difference Between Two Means, Two Propor difference in average television watching times between the two groups? Use a= 0.01. Children Teens bansta 18.50 Sample mean Sample variance Sample size 22.45 16.4 18.2 TS 15 15 Source: Time Almanac. 12. Professional Golfers' Earnings Two random samples of earnings of professional golfers were selected. One sample was taken from the Professional Golfers Associa- Professiona

10. Find the 95% confidence interv al ol ue uereice an means in Exercise 6 of this section. 11. Hours Spent Watching Television According to Nielsen Media Research, children (ages 2-11) spend an average of 21 hours 30 minutes watching television per week while teens (ages 12-17) spend an average of 20 hours 40 minutes. Based on the sample statis- tics shown, is there sufficient evidence to conclude a se at 9-19 498 Chapter 9 Testing the Difference Between Two Means, Two Propor difference in average television watching times between the two groups? Use a= 0.01. Children Teens bansta 18.50 Sample mean Sample variance Sample size 22.45 16.4 18.2 TS 15 15 Source: Time Almanac. 12. Professional Golfers' Earnings Two random samples of earnings of professional golfers were selected. One sample was taken from the Professional Golfers Associa- Professiona

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Description: I need help with question 11 please 10. Find the 95% confidence interval ol ue uereiceanmeans in Exercise 6 of this section.11. Hours Spent Watching Television According toNielsen Media Research, children (ages 2-11) spendan average of 21 hours 30 mi

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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4) The trade magazine QSR routinely checks the drive-through service times of fast-food restaurants. A 90% confidence interval that results from examing 607 customers in Taco Bell's drive-through has a lower bound of 161.6 seconds and an upper bound of 164.7 seconds. What does this mean?
If n = 340 and ˆpp^ (p-hat) = 0.6, construct a 95% confidence interval. According to the Oxnard College Student Success Committee report in the previous year, we believe that 21% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 99% confident that your estimate is within 5% of the true population proportion. How large of a sample size is required? Do not round mid-calculation.
The St. Lucie County Economic Development Board needs to estimate the proportion of all county residents who have earned at least a bachelor's degree. A random sample conducted by the St. Lucie County Economic Development Board found that 19.3% of all county residents held at least a bachelor's degree.Find three different confidence intervals - one with sample size 254, one with sample size 478, and one with sample size 668. Assume that 19.3% of the county residents in each sample have earned at least a bachelor's degree. Notice how the sample size affects the margin of error and the width of the interval.Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. When n=254, the margin of error for a 97% confidence interval is given by .When n=254, a 97% confidence interval is given by . When n=478, the margin of error for a 97% confidence interval is given by .When n=478, a 97% confidence interval…
3.Michael wants to make a confidence interval estimate for the proportion of community members in favor of a tax increase for more local school funding. If he wants the margin of error to be no more than 0.025 at a 90% confidence level, a)What is the required sample size required to obtain the desired margin of error
The Okeechobee County Economic Development Board needs to estimate the proportion of all county residents who have earned at least a bachelor's degree. A random sample conducted by the Okeechobee County Economic Development Board found that 10.5% of all county residents held at least a bachelor's degree.Find three different confidence intervals - one with sample size 180, one with sample size 451, and one with sample size 621. Assume that 10.5% of the county residents in each sample have earned at least a bachelor's degree. Notice how the sample size affects the margin of error and the width of the interval.Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. When n=180n=180, the margin of error for a 95% confidence interval is given by .When n=180n=180, a 95% confidence interval is given by . When n=451n=451, the margin of error for a 95% confidence interval is given by .When n=451n=451, a…
Suppose that, for budget planning purposes, the city in the previous exercise needs a better estimate of the mean daily income from parking fees. a) Someone suggests that the city use its data to create a 95% confidence interval instead of the 90% interval first created. How would this interval be better for the city? (You need not actually create the new interval.) b) How would the 95% interval be worse for the planners? c) How could they achieve an interval estimate that would better serve their planning needs?
The St. Lucie County Economic Development Board needs to estimate the proportion of all county residents who have earned at least a bachelor's degree. A random sample conducted by the St. Lucie County Economic Development Board found that 20.8% of all county residents held at least a bachelor's degree.Find three different confidence intervals - one with sample size 487, one with sample size 777, and one with sample size 938. Assume that 20.8% of the county residents in each sample have earned at least a bachelor's degree. Notice how the sample size affects the margin of error and the width of the interval.Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. When n=487n=487, the margin of error for a 95% confidence interval is given by .When n=487n=487, a 95% confidence interval is given by . When n=777n=777, the margin of error for a 95% confidence interval is given by .When n=777n=777, a 95%…
The Indian River County Economic Development Board needs to estimate the proportion of all county residents who have earned at least a bachelor's degree. A random sample conducted by the Indian River County Economic Development Board found that 28.7% of all county residents held at least a bachelor's degree. Find three different confidence intervals - one with sample size 387, one with sample size 556, and one with sample size 854. Assume that 28.7% of the county residents in each sample have earned at least a bachelor's degree. Notice how the sample size affects the margin of error and the width of the interval. Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. When n=387 the margin of error for a 99% confidence interval is given by =When n=387, a 99% confidence interval is given by = When n=556, the margin of error for a 99% confidence interval is given by =When n=556, a 99% confidence…
2. Suppose Netflix conducts a nation-wide survey to assess viewer habits regarding the show Ozark. Using a simple random sample, they select 8,000 men and 6,500 women to participate in the study. 7,102 of the men say that they watch Ozark, compared to 4,817 of the women.a. Estimate the difference in viewing habits of Ozark using a 95% confidence interval. b.Write a real world interpretation of this problem.
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Suppose we want to calculate a 99% confidence interval for the difference between the proportions of Californians and Oregonians who are sleepdeprived. 1. State the critical value for the interval (3 decimal places): 2. State the difference between the sample proportions, POregon-PCalifornia (3 decimal places): 3. State the standard error of the difference between the proportions (3 decimal places): 4. State the confidence interval being sure to use proper notation (3 decimal places each):
Suppose a retailer claims that the average wait time for a customer on its support line is 185 seconds. A random sample of 53 customers had an average wait time of 177 seconds. Assume the population standard deviation for wait time is 53 seconds. Using a 95% confidence interval, does this sample support the retailers claim? A) Yes, because the retailers claim is beteeen the lower limit of __ seconds and the upper limit of __ seconds for the mean wait time. B) No, because the retailers claim is not between the lower limit of __ seconds and the upper limit of __ seconds for the mean wait time. Please help!
21 this question has part a,b, and c Based on the confidence interval, the quality control department ---Select--- should or should not be concerned. Since 1 is ---Select--- contained in, below, above the interval, the interval ---Select--- suggests or does not suggest that ? is different from 1.