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10.25 For the system ethylene(1)/propylene(2) as a gas, estimate f1, f2, 1, and 2 at t = 150°C, P = 30 bar, and y₁ = 0.35: (a) Through application of Eqs. (10.63). P In $1 = R7B₁1 1 + y² 812) P In $2 = R7(B22 + y² 812) RT (10.63a) (10.63b)

10.25 For the system ethylene(1)/propylene(2) as a gas, estimate f1, f2, 1, and 2 at t = 150°C, P = 30 bar, and y₁ = 0.35: (a) Through application of Eqs. (10.63). P In $1 = R7B₁1 1 + y² 812) P In $2 = R7(B22 + y² 812) RT (10.63a) (10.63b)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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[1] Ch. 10 #25a. Given B₁1 = -60, B22 = -159, and B₁2 = -99 cm³/mol
Transcribed Image Text:[1] Ch. 10 #25a. Given B₁1 = -60, B22 = -159, and B₁2 = -99 cm³/mol
10.25 For the system ethylene(1)/propylene(2) as a gas, estimate f1, f2, 1, and $2 at t = 150°C, P = 30 bar, and y₁ = 0.35: (a) Through application of Eqs. (10.63). P In 41 = 27 (B₁1 + y² 812) RT In $₂ = = P RT (B22 + y² 812) (10.63a) (10.63b)
Transcribed Image Text:10.25 For the system ethylene(1)/propylene(2) as a gas, estimate f1, f2, 1, and $2 at t = 150°C, P = 30 bar, and y₁ = 0.35: (a) Through application of Eqs. (10.63). P In 41 = 27 (B₁1 + y² 812) RT In $₂ = = P RT (B22 + y² 812) (10.63a) (10.63b)
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