Question
Asked Nov 10, 2019
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Phorphoric acid is a triprotic acid, ionizing in the following sequential steps: (see attached image)

What is the the Kb expression for the base, sodium phosphate? 

a. Ka3

b. 1/Ka3

c. KW/Ka3

d. KwxKa3

e. Kw3/Ka1xKa2xKa3

105. Phosphoric acid is a triprotic acid, ionizing in the following sequential steps:
8
К,
Н.РО, + H.0 н,РО, + Н,О-
Ка,
H POHOsHPOHO
Кл,
HPO H2OS PO HO
What is the K expression for the base, sodium phosphate?
а. К
d. КхК,,
кр
К, хК, хК.
1
b.
К.,
е.
K
с.
К,
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105. Phosphoric acid is a triprotic acid, ionizing in the following sequential steps: 8 К, Н.РО, + H.0 н,РО, + Н,О- Ка, H POHOsHPOHO Кл, HPO H2OS PO HO What is the K expression for the base, sodium phosphate? а. К d. КхК,, кр К, хК, хК. 1 b. К., е. K с. К,

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Expert Answer

Step 1

The equilibrium constant for water, Kw is given as:

Н.О (1) + H-О () — Н:0* + ОН
Kw - [Нз0"] [ОН ]
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Н.О (1) + H-О () — Н:0* + ОН Kw - [Нз0"] [ОН ]

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Step 2

The given equations for triprotic phosphoric acid are:

H3PO4H2OH2PO4 +H3O
Kal
..(1)
Н.РО4 + H20 НРО42- + Hз0+
Ka2
.(2)
НРО42- + Н20+ РO43- + НзО*
Ka3 .....(3)
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H3PO4H2OH2PO4 +H3O Kal ..(1) Н.РО4 + H20 НРО42- + Hз0+ Ka2 .(2) НРО42- + Н20+ РO43- + НзО* Ka3 .....(3)

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Step 3

The dissociation of sodium phosphate can be written as:

Na3PO4 ↔ 3 Na+ + PO43-

Here, the conjugate base is PO43-

The equation for the dissociation of the base in water PO43- can be written as:

PO43- + H2O (l) ↔ HPO42- + ...

РО+ H.О ()
НРО2- + ОН
[(НРОД)2-] [он-]
К -
[(РОд)3-]
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РО+ H.О () НРО2- + ОН [(НРОД)2-] [он-] К - [(РОд)3-]

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