10A i1 V i2 A0 i2 13 14 20/0° V : :-2.5A 21, At node 2: i2+i4 =i3 V1-V2 + 2i, =V2 ...(3) j4 j2 but i = V1 -j2.5 jV1 2.5 Therefore V1-V2 j4 2 V1 - V2 2.5 j2 or (-j) V1-V2 + 2iV1 -(-)V2 2.5 2 Multiplying by 20 (-j)5(V1-V2) + j16V1 +j10V2 = 0 -15V1 + J5V2+ J16V1 +j10V2= 0 11V1 +15V2 = 0 - (4) .....
10A i1 V i2 A0 i2 13 14 20/0° V : :-2.5A 21, At node 2: i2+i4 =i3 V1-V2 + 2i, =V2 ...(3) j4 j2 but i = V1 -j2.5 jV1 2.5 Therefore V1-V2 j4 2 V1 - V2 2.5 j2 or (-j) V1-V2 + 2iV1 -(-)V2 2.5 2 Multiplying by 20 (-j)5(V1-V2) + j16V1 +j10V2 = 0 -15V1 + J5V2+ J16V1 +j10V2= 0 11V1 +15V2 = 0 - (4) .....
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Good day! My question is that how come that the equation 4 in this image(located in the last part) doesn't have letter j on it? Thank you!
![10A i1 V i2
i2 2
13
ww
14
20/0º V
-12.5 A
21,
At node 2:
i2+i4 =i3
V1-V2
+ 2i, = V2 .(3)
j4
....
j2
but i =
V1
= jV1
2.5
%3D
-j2.5
Therefore V1V2 + 2 =
V2
j2
%3D
j4
or (-j) V1-V2
2 V1 =(-1)V2
2.5
2
Multiplying by 20
(-j)5 (V1-V2) + j16V1 +j10V2 = 0
-j5V1 + J5V2+ ]16V1 +j10V2 = 0
· (4)
11V1 +15V2 = 0
.....](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2076238-b7b7-41e0-be73-0463d9d66615%2Fccbfef98-807f-4df0-bf7f-a778e94c730c%2F4wzg87n_processed.png&w=3840&q=75)
Transcribed Image Text:10A i1 V i2
i2 2
13
ww
14
20/0º V
-12.5 A
21,
At node 2:
i2+i4 =i3
V1-V2
+ 2i, = V2 .(3)
j4
....
j2
but i =
V1
= jV1
2.5
%3D
-j2.5
Therefore V1V2 + 2 =
V2
j2
%3D
j4
or (-j) V1-V2
2 V1 =(-1)V2
2.5
2
Multiplying by 20
(-j)5 (V1-V2) + j16V1 +j10V2 = 0
-j5V1 + J5V2+ ]16V1 +j10V2 = 0
· (4)
11V1 +15V2 = 0
.....
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