11. A 50 kVA, 2200/110 V transformer when tested gave the following results : O. test (L.V. side): 400 W, 10 A, 110 V. S.C. test (H.V. side): 808 W, 20.5 A, 90 v. Compute all the parameters of the equivalent ckt. referred to the H.V. side and draw the resultant ckt.
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- A single-phase 100-kVA,2400/240-volt,60-Hz distribution transformer is used as a step-down transformer. The load, which is connected to the 240-volt secondary winding, absorbs 60 kVA at 0.8 power factor lagging and is at 230 volts. Assuming an ideal transformer, calculate the following: (a) primary voltage, (b) load impedance, (c) load impedance referred to the primary, and (d) the real and reactive power supplied to the primary winding.An infinite bus, which is a constant voltage source, is connected to the primary of the three-winding transformer of Problem 3.53. A 7.5-MVA,13.2-kV synchronous motor with a sub transient reactance of 0.2 per unit is connected to the transformer secondary. A5-MW,2.3-kV three-phase resistive load is connected to the tertiary Choosing a base of 66 kV and 15 MVA in the primary, draw the impedance diagram of the system showing per-unit impedances. Neglect transformer exciting current, phase shifts, and all resistances except the resistive load.Consider Figure 3.25 of the text for a transformer with off-nominal turns ratio. (i) The per-unit equivalent circuit shown in part (c) contains an ideal transformer which cannot be accommodated by some computer programs. (a) True (b) False (ii) In the - circuit representation for real c in part (d), the admittance parameters Y11 and Y12 would be unequal. (a) True (b) False (iii) For complex c, can the admittance parameters be synthesized with a passive RLC circuit? (a) Yes (b) No
- A single-phase two-winding transformer rated 90MVA,80/120kV is to be connected as an autotransformer rated 80/200kV. Assume that the transformer is ideal. (a) Draw a schematic diagram of the ideal transformer connected as an autotransformer. showing the voltages, currents, and dot notation for polarity. (b) Determine the permissible kVA rating of the autotransformer if the winding currents and voltages are not to exceed the rated values as a two-winding transformer. How much of the kA rating is transferred by magnetic induction?Consider Figure 3.4. For an ideal phase-shifting transformer, the imda nce is unchanged when it is referred from one side to the other. (a) True (b) FalseThe transformer of Problem 3.16 is supplying a rated load of 50 kVA at a rated secondary voltage of 240 V and at 0.8 posr factor lagging. Neglect the transformer exciting current. (a) Determine the input terminal voltage of the transformer on the high-voltage side. (b) Sketch the corresponding phasor diagram. (c) If the transformer is used as a step-down transformer at the load end of a feeder whose impedance is 0.5+j2.0, find the voltage VS and the power factor at the sending end of the feeder.
- Consider a source of voltage v(t)=102sin(2t)V, with an internal resistance of 1800. A transformer that can be considered as ideal is used to couple a 50 resistive load to the source. (a) Determine the transformer primary-to-secondary turns ratio required to ensure maxi mum power transfer by matching the load and source resistances. (b) Find the average power delivered to the load, assenting maximum power transfer.A 120:480-V, 10-kVA step-up two-winding transformer is to be used as an autotransformer to supply a 120-V circuit from a 600-V source (a step-down autotransformer). When it is tested as a two-winding transformer at rated load, unity power factor, its efficiency is 97.9 %. 1.Show the connection diagram of the transformer converted as an autotransformer and identify which is the series winding Nse and the common winding Nc.630kVA 31500/400 DY 50Hz transformer has no load and short circuit tests power measurements are given as 1kW and 20kW respectively. Under the fourth of the nominal load with 0,85 capacitive power factor, calculate the efficiency of the transformer at nominal voltage as %?
- A transformer with a 10:1 ratio and rated at 60kVA, 2200/220V, 60Hz is used to step down the voltage of a distribution system. The low tension voltage is to kept constant at 220V. (a) What load Impedance connected to the low-tension side will be loading the transformer fully at 0.8 power factor (lag) ? (b) What is the value of this impedance referred to the high tension side?A single-phase l0-kVA, 480/1120 -V transformer is to be used as an auto transformer tying a 600V distribution line to a 480-V load. When it is tested as a conventional transformer, the following values are measured on the primary (480-V) side of the transformer: a. Find the per-unit equivalent circuit of this transformer when it is connected in the conventional manner. b. What is the efficiency of the transformer at rated conditions and unity power factor? c. What is the voltage regulation at those conditions?A Transformer with 10:1 ratio and rated at 50-kVA, 2400/240-V, 50-Hz is used to step down the voltage of a distribution system. The low-tension voltage is to be kept constant, if the transformer has: R = 2.2 0, R2 = 0.014 Q, X, = 4.1 0, X2 = 0.03 0, then, a. What load impedance connected to low-tension side will be loading the transformer fully. b. Calculate the equivalent resistance as referred to primary. c. Calculate the equivalent reactance as referred to primary. d. Calculate the equivalent impedance as referred to primary. e. Calculate the total Cu loss.