11% of all Americans live in poverty. If 42 Americans are randomly selected, find the probability that a. Exactly 6 of them live in poverty. b. At most 6 of them live in poverty. c. At least 6 of them live in poverty. d. Between 5 and 13 (including 5 and 13) of them live in poverty. Hint:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Question 15
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11% of all Americans live in poverty. If 42 Americans are randomly selected, find the probability that
a. Exactly 6 of them live in poverty.
b. At most 6 of them live in poverty.
c. At least 6 of them live in poverty.
d. Between 5 and 13 (including 5 and 13) of them live in poverty.
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Video on Finding Binomial Probabilities [+]
Transcribed Image Text:Question 15 ▼ < > 11% of all Americans live in poverty. If 42 Americans are randomly selected, find the probability that a. Exactly 6 of them live in poverty. b. At most 6 of them live in poverty. c. At least 6 of them live in poverty. d. Between 5 and 13 (including 5 and 13) of them live in poverty. Submit Question Hint: Hint Video on Finding Binomial Probabilities [+]
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