12. Complete the benchmark-leveling field notes shown in Figure B by computing and recording the HI and elevation for each TP and benchmark. Do the arithmetic check. Sta. BS BM 10 TP 1 TP 2 TP 3 TP 4 0.876 BM 20 Sum= 1.567 1.345 1.136 0.987 HI FS Elev. 200.00 3.579 2.760 2.575 2.055 1.579

12. Complete the benchmark-leveling field notes shown in Figure B by computing and recording the HI and elevation for each TP and benchmark. Do the arithmetic check. Sta. BS BM 10 TP 1 TP 2 TP 3 TP 4 0.876 BM 20 Sum= 1.567 1.345 1.136 0.987 HI FS Elev. 200.00 3.579 2.760 2.575 2.055 1.579

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

In the two-peg test of a dummy level, the following observations are taken. On point A On point B INSTRUMENT SET UP at M 2.682 1.239 INSTRUMENT SET UP at P 1.876 0.565 Point M is equidistance from both A and B with 92 meters, while P is 2.50m away from A along the extension of line AB. Requirements: Determine the true difference in elevation between point A and B. With the level still set up at P, determine the rod reading on A and B to which the line of sight should be adjusted. If the instrument needs to be adjusted, determine the following false difference in elevation inclination of the line of sight and the error in the reading of far rod A and B instrument set up at P.
Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).
Solve by Rise and fall method Ques- The following consecutive readings were taken with dumpy level and 4 m levelling staff on continuously sloping ground at a common interval of 30 m. 0.585 on A, 0.936, 1.953, 2.846, 3.644, 3.938, 0.962, 1.035, 1.689, 2.534, 3.844, 0.956, 1.579, 3.016 on B. The elevation of A was 520.450 m. (a) Enter the readings in level book. (b) Calculate R.L. of all the points by rise - fall method. (c) Apply usual arithmetical checks. (d) Determine the gradient of line AB.
A level line from P to Q is carried out to and fro direct leveling, and the height difference of the forward measurement is 12.380 meters, and the height difference of the back measurement is 12.411 meters. It is also known that the closed difference limit value of the previous test and the back test K is 20 mm (K is the number of kilometers), the forward measuring level is 4.2 kilometers long, and the back measuring level is 3.5 kilometers long. Try to find the average elevation difference from P to Q, and whether the round-trip test results meet the regulations, and please explain your answer.
A dumpy level is set up at one end of a line 120 m long for the purpose of determining the instrument’s stadia interval factor. The line is marked by hubs at every 30 m and a stadia rod is held at each hub. The stadia intercepts at each location of the rod were observed as follows: 0.308, 0.613, 0.918 and 1.222 meters, respectively. The average value of the instrument’s stadia interval factor is:
From the following differential leveling notes, compute the difference in elevation between stations 5 and 6. a. 2.62 b. 1.61 c. 3.51 d. 1.87
RECIPROCAL LEVELING. In reciprocal leveling across a deep ravine the following sets of rod readings were takent: Instr Near A: BS on A=1.719 m, Average Fs on B=2.578 m Instr Near B: Average BS on A=1.335 m, FS n B=2.176 m Point A is on one side of the ravine and has a known éle- vation of 197.428 m. Point B is on the other side. Deter- mine the elevation of point B.
1. A tachometric surveying was conducted to obtain some readings for inaccessible points, where it was found that the multiplying and additive constants are 98 and 0.1, respectively. The instrument was setup at point C and the readings listed in the table were taken while the staff was held vertically. Calculate the horizontal distance between BM and station D. Also, calculate the reduced level of station D. Figure 1 shows a schematic view of the site. 2. Describe a practical procedure to measure the height of your house using tachometric surveying, list the procedure in bullet points.
For all the computed values with decimals, use four (4) digits after the decimal. Differential leveling runs from BM10 to BM11 at a distance of 7.5 km. It was observed that the leveling rod was inclined 6° from the vertical every time the backsight is taken. The average BS reading is 3.15m and the average length per set-up is 300m. Determine the error every 300m set-up and the correct elevation of BM11 if the recorded elevation was 173.20m.
During the dumpy level test, the observations are as follows:Staff reading stationAInstrument placedB2.2353.545AB1.6052.564Distance between A and B is 250 m and R.L of A is 435.062 m, Find the R.L of B.
An inverse method of leveling is executed between two existing concrete structures and across a concrete wall located midway between the two structures. All rod readings, as indicated in the sketch, were taken with the rod held upside down. From the data portrayed, if the elevation of A (bottom of the concrete beam of the first structure) is 240.05 m., the elevation of the bottom of the concrete beam of the second structure (indicated as C) should be
A transit with a stadia constant equal to 0.30 is used to determine the horizontal distance betweeen points B and C, with a stadia intercept reading of 1.75 m, the distance BC is equal to 185.87m. Using the same instrument, it was used to determine the difference in elevation between B and D having a stadia intercept reading of 2.42 m at D at a vertical angle of (+) 6-30-00. Compute the difference in elevation of B and D. a.26.91 b. 28.90 c. 22.78 d. 23.78