12. The combustion of glucose is represented by the following balanced equation: CgH1206 +6 O2 6 H20+6 CO2. Which reactant is the limiting reagent if there is 1 gram of both C6H2O6 and O2? a. CH1206 b. H20 с. Оз d. CO2
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- Using the percent purity calculations, determine the percent yield of synthesis of aspirin. Part I Synthesis of Aspirin Mass of salicylic acid used (g) 2.029g Volume of acetic anhydride used (mL) 5ml Mass of acetic anhydride used (vol. × 1.08 g/mL) 5.4g Mass of aspirin synthesized (g) 3.256g Part II Melting Temperature Data Melting temperature (°C) 133°C Part III Salicylic Acid Standard Stock Solution Initial mass of salicylic acid (g) 0.210g Moles of salicylic acid (mol) 0.0147 mol Initial molarity of salicylic acid (M) 0.724 M Part III Beer’s Law Data for Salicylic Acid Standard Solutions Trial Concentration (M) Absorbance Water (mL) 1 10 0.301 0 2 7.5 0.219 2.5 3 5.0 0.163 5.0 4 2.5 0.074 7.5 Best-fit line equation for the salicylic acid standards Test of the Purity of the Synthesized Aspirin Initial mass of aliquot of product (g)…Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction isConsider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction is a. rate = k[H2O2][I–][H+] b. rate = k[H2O2][H+] c. rate = k[H2O2]2[I–]2[H+]2 d. None of these e. rate = k[H2O2][I–] f. rate = k[I–][H+]
- Consider the following data concerning the equation: H2O2 + 3I– + 2H+ → I3– + 2H2O [H2O2] [I–] [H+] rate I 0.100 M 5.00 × 10–4 M 1.00 × 10–2 M 0.137 M/sec II. 0.100 M 1.00 × 10–3 M 1.00 × 10–2 M 0.268 M/sec III. 0.200 M 1.00 × 10–3 M 1.00 × 10–2 M 0.542 M/sec IV. 0.400 M 1.00 × 10–3 M 2.00 × 10–2 M 1.084 M/sec The rate law for this reaction is a. rate = k[H2O2]2[I–]2[H+]2b. rate = k[I–]c. None of thesed. rate = k[I–][H+]e. rate = k[H2O2][I–][H+]f. rate = k[H2O2][H+]Na2CO3(aq) + CaCl2⋅2H2O → CaCO3(s) + 2NaCl(aq) + 2H2O(aq) It has been previously determined that : there are 1.50 grams of CaCl2⋅2H2O there are .0102 moles of pure CaCl2 and 1.081g of Na2CO3 is need to reach stochiometric quantities What is the maximum (theoretical) amount of CaCO3 in grams that can be produced from the precipitation reaction?Magnesium +Acetic Acid --> C2HG5+ O2 ---> Iron (III) carbonate -->
- COMPLETE SOLUTION with given and required ASAP You will be defining a new temperature scale in oX, in which the freezing and boiling points of water areone-hundred degrees X and one-thousand fifty-five oX, respectively. Correlate this to Celsius orFahrenheit scales. The oX reading on this scale is a certain number of degrees on a correspondingabsolute temperature scale. What is the corresponding absolute temperature at 0oX?93.6g to ng and 93.6g to tons with the set up in the image possible show how to get the answer pleaseStock iron(II) solution (200Ug mL-1 Fe) ferrous ammonium sulfate hexahydrate mass= 0.1437g, transfer it to a 100 ml beaker. add 15 ml approx of water and 15m1 'approx of dilute sulphuric acid (2M H2SO.). then transfer FeII to 100 ml flask makeup to the mark with water. calculate the moles of ferrous ammonium sulfate hexahydrate solution in unit ug/mL.
- A 1.59 g sample containing KI was analyzed gravimetrically and 0.0538g of Barium Iodate was recovered... express the results of this analysis as percent posassium iodide.Inorganic Chem Please help answering this question Use equation V = (N)(q1)(q2)(k) / r where k = 9.0x10^9The student then determined ΔH neutralization for the reaction of sodium hydroxide and acetic acid, using the procedure described in this module. The student added 100.0 mL of 0.8500M NaOH to 100.0 mL of 0.8404M acetic acid. Prior to and following the mixing of the acid and base solutions, the following temperature-time data were collected. g) Identify the limiting reagent and briefly explain why it is limiting. h) Find ΔH neutralization for the reaction.