. Aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (AIC13) according to the balanced equation: In a certain experiment, 10.0 g of aluminum is reacted with 35.0 g of chlorine gas. a. How many moles of aluminum chloride would be produced in this complete reaction? b. Which substance is the limiting and excess reagent? c. How many moles of the excess reagent is left after the reaction? 2 Al(s) + 3 Cl2 () 2 AICI3 (s)

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2. Aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (A1C13) according
to the balanced equation:
In a certain experiment, 10.0 g of aluminum is reacted with 35.0 g of chlorine gas.
a. How many moles of aluminum chloride would be produced in this complete reaction?
b. Which substance is the limiting and excess reagent?
c. How many moles of the excess reagent is left after the reaction?
2 Al(s) + 3 Cl2 (g)
2 AIC13 (s)
Transcribed Image Text:2. Aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (A1C13) according to the balanced equation: In a certain experiment, 10.0 g of aluminum is reacted with 35.0 g of chlorine gas. a. How many moles of aluminum chloride would be produced in this complete reaction? b. Which substance is the limiting and excess reagent? c. How many moles of the excess reagent is left after the reaction? 2 Al(s) + 3 Cl2 (g) 2 AIC13 (s)
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