12. The normal boiling point of 2-propanol, (CH3)2CHOH, is 83°C, while that of acetone, (CH3)2C=0, is 56°C. What is the principal reason for the greater boiling point of 2-propanol. a. The O-H bond in 2-propanol is stronger than the C-H bond in acetone. b. 2-propanol experiences greater London dispersion forces than acetone. c. 2-propanol experiences stronger dipole-dipole interactions than acetone. d. 2-propanol experiences stronger hydrogen bonding than acetone.

12. The normal boiling point of 2-propanol, (CH3)2CHOH, is 83°C, while that of acetone, (CH3)2C=0, is 56°C. What is the principal reason for the greater boiling point of 2-propanol. a. The O-H bond in 2-propanol is stronger than the C-H bond in acetone. b. 2-propanol experiences greater London dispersion forces than acetone. c. 2-propanol experiences stronger dipole-dipole interactions than acetone. d. 2-propanol experiences stronger hydrogen bonding than acetone.

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 20CR

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