13.) For the RAM : -> %3D AHp f AgBr= -100.4kJ △Hp g Brg aー+30,9J + 30.9kJ Frd fhe he at f Ranacion for AzIGS) g formatian for AgICS) -54.0=(-100,4) -(5• 30.9) - X 61.85=-X 1 - 61.858y=X
13.) For the RAM : -> %3D AHp f AgBr= -100.4kJ △Hp g Brg aー+30,9J + 30.9kJ Frd fhe he at f Ranacion for AzIGS) g formatian for AgICS) -54.0=(-100,4) -(5• 30.9) - X 61.85=-X 1 - 61.858y=X
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.10QAP
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See image below. Can you please show me how to solve this (i.e. why we don't add the 100.4, etc.)?
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