13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? X (Show the cross to prove it!)

13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? X (Show the cross to prove it!)

Name: 13. In guinea pigs, the allele for short hair is dominant over long h
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Description: 13. In guinea pigs, the allele for short hair is dominant over long hair.Two short haired guinea pigs are mated several times. Out of 100offspring, 25 of them have long hair.What are the probable genotypesof the parents?(Show the cross to prove it!)

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 3GP: Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With...

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A testcross is a way to determine ________. a. phenotype b. genotype c. dominance
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?
1. In pea plants, yellow color (Y) is dominant over green color (y). A yellow-colored pea plant is crossed with a green-colored pea plant. Half of their offspring is yellow-colored while the other half is green-colored.What is the genotype of the yellow-colored parent? YY O Yy yy The genotype cannot be determined. 2. A scientist discovered an unknown organism in a tropical rainforest. The organism has been identified to possess the following characteristics: (1) multicellular at some point of its life cycle; (2) feeds on decaying organic matter; and (3) has a cell wall made of chitin.Which Kingdom does the unknown organism likely belong to? Kingdom Animalia Kingdom Plantae Kingdom Fungi Kingdom Protista 3. Which statement about ferns is TRUE? Ferns are unicellular organisms. Ferns are nonvascular plants. O Ferns have spores as reproductive structures. Ferns are capable of secondary growth.
4. The ruffed chicken has an under-chin wattle. A smooth wattle (S) is dominant over a wrinkled wattle (s). A red wattle (HR) is incompletely dominant with a white wattle (HW) so that an individual with HRHW will have a pink wattle. A chicken with a wrinkled red wattle is mated to a homozygous chicken with a smooth white wattle. What is the genotype and phenotype of the chicks?
1. How many different types of gametes can be produced by an individual with the genotype Yy Ww Pp ee Bb? 2. If an individual with the genotype Yy Ww Pp ee Bb is crossed with another individual with the same genotype, what proportion of offspring will be homozygous recessive at all genes? 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci?
10. What phenotypes are expected and in what proportion from each of the following n crosses? (Assume D, G and Ware dominant over d, g and w, respectively.) 31 (a) DdGGww x DDGgWw how bon (b) ddggWw x DdGgww HD: (c) DdGgWw x DdggWw (d) DdGgWW x DdGgWW baildhalos 6 am bunjid-roloos (d) nomow sof bemam nam lemona (0) namnow beild-oloss of bemem nem tarono [b) int euogyson M 11. Radishes can be long, round or oval in shape. They may be red, white or purple in color. A long red variety was crossed with a round white variety. In the F₁ generation, all were oval purple. In the F2 generation, there were 8 long red, 15 long purple, 17 oval red, 31 oval purple, 7 long white, 15 oval white, 8 round red, 16 round purple and 9 round white. Explain the genetic basis of these results. hot tmsidorss endohes barlastis bed terftet ben hemouth bra (Jisi edohss srillo sonsmedni Snem ar to gaylonog ori ai fer msil) ov fa cisiv lemon diw be (!) 12. In shorthorn cattle, the allele for red coat color (R) is…
10. If B=brown eyes and b=blue eyes, and a man with brown eyes and a woman with blue eyes have a child with blue eyes, what is the genotype of the man for eye color? Assume complete dominance. * BB ВB or Bb Bb brown can't tell without more information
10. In the video example, the sex-linked disorder was a recessive trait. However, sex-linked disorders can be dominant! (Conduct a search to see some of the sex-linked dominant disorders that exist). Sex- linked dominant disorders will show even if there is only one dominant allele present. Using the allele D to stand for a dominant sex-linked trait, show a cross with a woman who does not have a dominant sex-linked disorder (X*Xª) with a man that does. Will the disorder in this particular cross be more common in daughters or sons?
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
2. The presence of horns on Hereford cattle is controlled by a single gene. The hornless (H) condition is dominant over the horned (h) condition. A hornless cow was crossed repeatedly with the same horned bull. The following results were obtained in the F, offspring: 8 hornless cattle 7 horned cattle What are the parents' genotypes? cow bull
1. Count out 60 black beans and 40 white beans into the baggie. Let the black beans represent the dominant allele A, and the white beans represent the recessive allele a, in the gene pool. This is your F0 generation. 2. Without looking, randomly remove two beans from the baggie. This represents one diploid individual offspring in the next (F1) generation. Tally the diploid genotypes of the offspring formed by these two gametes in Table 1 below. 3. Return the two beans back to the bag and gently shake it to reinstate the random gene pool. By returning the beans after each selection, the size of the gene pool remains constant and the probability of selecting any allele should remain equal to its frequency in the gene pool. Repeat this 50 times, meaning 50 individual diploid organisms. 4. Make sure to return all beans to the baggie. 5. Repeat this procedure (steps 2-3) (for your F2 generation) until you have recorded the genotypes of another 50 individuals.
For questions 1-3, consider a pea plant homozygous for tall stems and green seeds crossed with a plant dihybrid for tall stems and yellow seeds.