AnswerNumber 14 13. Manually debug the program below. Write the correct thestatement/s to make it run.import java.util.Scanner;public class secondclass {public static void main(String[] args){Scanner obj =new Scanner (;int a;int b-5;System.out.println("Enter number 5.");a = obj.nextInt();%3DSystem.out.println("The sum of a and b is " + (a+b));{int] counter = new int[5]14. Write a program that will accept two integer values in an input dialog 10 poinbox. Get the higher value and show it in a message dialog box.Your answer9 This is a required questionSubmitClear forNever submit passwords through Google Forms.This content is neither created nor endorsed by Google Report Abuse- Terms of Service- Privacy PolicyGoogle FormsEOEGO2.1.

import javax.swing.JOptionPane; public class Main { public static void main(String[] args) {…

Answered: 14. Write a program that will accept…

14. Write a program that will accept two integer values in an input dialog 10 box. Get the higher value and show it in a message dialog box. *

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Please write the script and introduction for the program so that the number of words is between 300-400 //importing scanner import java.util.Scanner; //our main class public class Main { //our main method public static void main(String args[]) { //declaring pegs int pegs; //declaring source,destination,middleone strings String source,destination,middleone; //creating scanner class Scanner mine = new Scanner(System.in); //asking number of pegs System.out.print("Please enter the number of pegs: "); //user input pegs=mine.nextInt(); //to the nextline mine.nextLine(); //printing System.out.print("Please enter the source name: "); //user input source=mine.nextLine(); //printing…
JAVA Program ASAP Please modify this program and take out the main method from the program so it passes the test cases in Hypergrade. I have provided the failed test cases. import java.io.BufferedReader;import java.io.FileReader;import java.io.IOException;import java.util.ArrayList;import java.util.Arrays;import java.util.InputMismatchException;import java.util.Scanner;public class FileSorting { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while (true) { System.out.println("Please enter the file name or type QUIT to exit:"); String fileName = scanner.nextLine(); if (fileName.equalsIgnoreCase("QUIT")) { break; } try { ArrayList<String> lines = readFile(fileName); if (lines.isEmpty()) { System.out.println("File " + fileName + " is empty."); } else { performSorting(lines);…
Please sort out the following JAVA code....line by line. Run the code in Netbeans and provide screenshots to verify that it runs successfully. CODE: import java.io.*; import java.util.*; public class experiment { public static void main(String args[]) { Scanner in=new Scanner(System.in); int time[]=new int[10]; float weight[]=new float[10]; String get; char ch; int i=0; do{ try { System.out.print("\nEnter the time in seconds:"); time[i]=in.nextInt(); System.out.print("\nEnter the weight in kilograms:"); weight[i]=in.nextFloat(); i++; } catch(Exception e) { System.out.print("\nInvalid type"); } System.out.print("\n-----------------"); System.out.print("\n|Time\t|Weight\t|"); System.out.print("\n-----------------"); for(int x=0;x<i;x++) { System.out.print("\n|"+time[x]+"\t|"+weight[x]+"\t|"); System.out.print("\n-----------------"); } if(i==10) { for(int x=0;x<9;x++) { time[x]=time[x+1]; weight[x]=weight[x+1]; } i--; } System.out.print("\nDo you want to continue?(y/n) ");…
1. In this Java program. Explain everyline of this code. Source Code: import java.util.*;public class Main{ public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); System.out.print("Enter the number of lockers: "); int noOfLockers = keyboard.nextInt(); boolean[] isLockerOpen = new boolean[noOfLockers + 1]; for (int i = 1; i <= noOfLockers; i++) { for (int j = i; j <= noOfLockers; j += i) { isLockerOpen[j] = !isLockerOpen[j]; } }     System.out.println("\n\nThe number of lockers: " + noOfLockers); System.out.println("The locker numbers of the lockers that are open: "); for (int i = 1; i <= noOfLockers; i++) { if (isLockerOpen[i] == true) System.out.print(i + " "); } }}
I need help with a Java question so that it can output them described in the image below: import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int[] userList = new int[20];   int numElements; numElements = scnr.nextInt(); for (int i = 0; i < numElements; i++) { userList[i] = scnr.nextInt(); } for (int i = numElements - 1; i >= 0; i--) { System.out.print(userList[i]); if (i > 0) { System.out.print(","); } } }}
I need help with this Java Problem as described in the image below: import java.util.Scanner; public class LabProgram {    public static int fibonacci(int n) { /* Type your code here. */    }    public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int startNum;     startNum = scnr.nextInt(); System.out.println("fibonacci(" + startNum + ") is " + fibonacci(startNum)); }}
Answer with a given JAVA question below. Consider the following code: public class Quiz{ public String name; public double totalPoints; public String getName() { return this.name; } public double getTotalPoints() { return this.totalPoints; } } Based on the Java code, explain where information hiding is being violated, why it is considered a violation, and how a programmer should fix the violation.
Please correct the error, I don't know where I mistake. currently it says I've mistake at import.java.util.*; import.java.util.*; public class Employee{ public static void main (String[] args) { DetailsEmployee deEmployee= new DetailsEmployee(); deEmployee.enterdetails(); NewEmployee neEmployee= new NewEmployee(); neEmployee.enteremployee(); } } class DetailsEmployee{ DetailsEmployee() { System.out.println("Employee"); } void enterdetails() { Scanner s=new Scanner(System.in); System.out.println("Enter name:"); String name=s.nextLine(); System.out.println("Enter Id:"); int Id=s.nextInt(); System.out.println("Enter position:"); String position=s.nextLine(); System.out.println("Enter salary:"); int salary=s.nextInt(); } }class NewEmployee{ NewEmployee() { System.out.println("New Employee is"); } void enteremployee() { Scanner s=new…
PLEASE REWIRETE THIS CODE USING "The J Option Pane Class" import java.util.Scanner;public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter money to withdraw: "); int amount = sc.nextInt(); if(amount <= 20) System.out.println("INSUFFICIANT AMOUNT"); else System.out.println("Collect your money! RM"+amount); }}
Draw an Activity diagram for the following code: import java.util.Scanner; public class Srs { public static void main (String ) args) { int a; Scanner in = new Scanner(System.in), System.out.printin("Enter Your Age), a = in.nextint(), if (a < 13) System.out.prinln("You are a child); else if(a =>13) System.out.prinln("You are a Teenager"), else if(a =>20) System.out.prinln("You are an Adult"), else System.out.printn("You are You). Paragraph
WRITE THE BODY OF Java program - THE checkWinner METHOD BELOW SO THAT THE GAME STOPS WHEN SOMEONE WINS, OR WHEN THE BOARD IS FULL. AS SHOWN IN THE SAMPLE OUTPUT AT THE BOTTOM. Code: import java.util.Scanner; public class TicTacBoard { private char[][] board; // 2-D array of characters private char curPlayer; // the player whose turn it is (X or O) // Constructor: board will be size x size public TicTacBoard(int size) { board = new char[size][size]; // initialize the board with all spaces: for(int row=0; row < board.length; row++) for(int col=0; col < board[row].length; col++) board[row][col] = ' '; curPlayer = 'X'; // X gets the first move } public void playGame() { display(); do { takeTurn(); display(); }while(!checkWinner()); } /////// display //////// // Display the current status of the board on the // screen, using hyphens (-) for horizontal lines // and pipes (|) for vertical lines. public void…
Consider the following code in Java 8:public interface Runnable{void run() ;}public final class Caller {public static void call (String before, String after, Runnable r) (System.out.println(before);r. run() ;System.out.println(after);} }public class MyClass{public static void main(String args[]) (Caller.call("BEFORE", "AFTER",); } }Complete the blark line with some code so that the program prints the folowing to the output: BEFOREHi there!AFTER