I need help with a Java question so that it can output them described in the image below:import java.util.Scanner;public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int[] userList = new int[20]; int numElements; numElements = scnr.nextInt(); for (int i = 0; i < numElements; i++) { userList[i] = scnr.nextInt(); } for (int i = numElements - 1; i >= 0; i--) { System.out.print(userList[i]); if (i > 0) { System.out.print(","); } } }} 1:Compare outputOutput differs. See highlights below. Special character legendInputYour outputExpected output2:Compare output ^InputYour output3:Compare outputExpected output5 2 4 6 8 10Output differs. See highlights below.10, 8, 6, 4, 210, 8,6,4,.2,<6 42 53 19 18 100 12Special character legend12,100,18,19,53, 4212,100,18,19,53, 42, HInput 19Output differs. See highlights below. Special character legendYour output 9Expected output 9.4

Hеrе is an algorithm for thе Java codе you providеd:Crеatе an array to storе thе еlеmеnts еntеrеd by…

I need help with a Java question so that it can output them described in the image below: import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int[] userList = new int[20]; int numElements; numElements = scnr.nextInt(); for (int i = 0; i < numElements; i++) { userList[i] = scnr.nextInt(); } for (int i = numElements - 1; i >= 0; i--) { System.out.print(userList[i]); if (i > 0) { System.out.print(","); } } } }

I need help with a Java question so that it can output them described in the image below: import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int[] userList = new int[20]; int numElements; numElements = scnr.nextInt(); for (int i = 0; i < numElements; i++) { userList[i] = scnr.nextInt(); } for (int i = numElements - 1; i >= 0; i--) { System.out.print(userList[i]); if (i > 0) { System.out.print(","); } } } }

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter10: Pointers

Section10.1: Addresses And Pointers

Problem 5E

See similar textbooks

Similar questions

Transcribed Image Text Joshua, a systems administrator, is configuring new Windows 10 laptops. He is creating new local users on each laptop. He realizes that two users have the same name, Miguel. He uses the name Miguel for one user. Which of the following is a valid user name that he can create for the second user? a) Miguel? b) Mig c) Miguel d) Miguel2 e) All the above will work!
Q) Reorder the following code to speed up. How many number of clock cycles can be saved with this reordering? MOVE.W D1,D0ADD.W D0,D3 MULU D3,D1 LEA (A4),A6 MOVE.W #$3400,D2ADDA.W D7,A2 MOVE.W #$F6AA,D4
Convert thid code to Bash Script #include<stdio.h>int mutex=1,full=0,empty=3,x=0;main(){ int n; void producer(); void consumer(); int wait(int); int signal(int); printf(“\n 1.Producer \n 2.Consumer \n 3.Exit”); while(1) { printf(“\n Enter your choice:”); scanf(“%d”,&n); switch(n) { case 1: if((mutex==1)&&(empty!=0)) producer(); else printf(“Buffer is full”); break; case 2: if((mutex==1)&&(full!=0)) consumer(); else printf(“Buffer is empty”); break; case 3: exit(0); break; } }}int wait(int s){ return (--s);}int signal(int s){ return(++s);}void producer(){ mutex=wait(mutex); full=signal(full); empty=wait(empty); x++; printf(“\n Producer produces the item %d”,x); mutex=signal(mutex);}void consumer(){ mutex=wait(mutex); full=wait(full); empty=signal(empty);…
What is wrong with this statement? form1.text = 123 Select one: a. no error b. 123 should be “123” c. it should be == d. text should be txt It enables certain instruction or task to repeat. Select one: a. iteration b. all of the choices c. selection d. decision What keyboard shortcut is used to close a window in a DevC? Select one: a. SHIFT+CTRL+W b. SHIFT+CTRL+C c. CTRL+C d. CTRL+W
Question #1 There is a multiline string variable i.e. inputString = ‘Dell Display Manager’s (DDM) Easy Arrange feature lets you quickly tile and view your applications side by side across one or more connected screens for multitasking efficiency. And with the improved DDM, you’ll get even more preset layouts. The auto-restore feature remembers where you left off, so applications will go back to where you left them, even after you’ve unplugged.’ Write python code that: a. Prints inputString as it is. [Hint: use escape sequence] b. Copies inputString into inputStringNew in a way that last sentence will become the first sentence of inputStringNew: inputStringNew = ‘The auto-restore feature remembers where you left off, so applications will go back to where you left them, even after you’ve unplugged. Dell Display Manager’s (DDM) Easy Arrange feature lets you quickly tile and view your applications side by side across one or more connected screens for…
Convert this code to bash script to simulate producer-consumer problem using semaphores. #include<stdio.h>int mutex=1,full=0,empty=3,x=0;main(){ int n; void producer(); void consumer(); int wait(int); int signal(int); printf(“\n 1.Producer \n 2.Consumer \n 3.Exit”); while(1) { printf(“\n Enter your choice:”); scanf(“%d”,&n); switch(n) { case 1: if((mutex==1)&&(empty!=0)) producer(); else printf(“Buffer is full”); break; case 2: if((mutex==1)&&(full!=0)) consumer(); else printf(“Buffer is empty”); break; case 3: exit(0); break; } }}int wait(int s){ return (--s);}int signal(int s){ return(++s);}void producer(){ mutex=wait(mutex); full=signal(full); empty=wait(empty); x++; printf(“\n Producer produces the item %d”,x); mutex=signal(mutex);}void consumer(){…
This problem deals with speedup and Amdahl’s Law.You are employed at ABC Computer Inc. as an engineer in their computerarchitecture division that produces the ABC-8 a desktop computer system. Thereare four possible performance improvements. However, the budget will only allowfor only one improvement. Your boss wants you to recommend the improvementthat will provide the greatest speedup and provide supporting justification. Theoptions are listed below.•Option A: Reduce the time needed for the Read operation to 900 ns.•Option B: Reduce the time needed for the Write operation to 1200 ns.
What will be the final value in EDX after this code executes? mov edx, 1 mov eax, 7FFFh cmp eax, 0FFFF8000h jl L2 mov edx,0 L2:
Which of the following is correct regarding Memory-Mapped I/O? Select one: a. Memory-Mapped I/O is more complex and inflexible in handling I/O operations. b. The same memory reference instructions (read/write) can be used for I/O transfers. c. There are separate input and output instructions to handle I/O data transfers. d. There is a separate memory and I/O address space. O e. The available memory address space is larger when using Memory-Mapped I/O.
Question 7 A serial transmitter with event: Tr_buf is a byte-wide buffer. Serially output its content on a serial line. When Tr_buf is empty, set event TR. On TR event, load Tr_buf from bottom of FIFO. write a verlog code using bhevarioial level Full explainthe this question very fast solution sent me step by step Don't ignore any part all part work u Text typing work only not allow paper work
⦁ You are required to make changes in the programs and introduce the use of compaction where required. MVT MEMORY MANAGEMENT TECHNIQUE#include<stdio.h>#include<conio.h>main(){int ms,mp[10],i, temp,n=0; char ch = 'y';clrscr();printf("\nEnter the total memory available (in Bytes)-- "); scanf("%d",&ms);temp=ms;for(i=0;ch=='y';i++,n++){printf("\nEnter memory required for process %d (in Bytes) -- ",i+1); scanf("%d",&mp[i]);if(mp[i]<=temp){printf("\nMemory is allocated for Process %d ",i+1); temp = temp - mp[i];}else{printf("\nMemory is Full"); break;}printf("\nDo you want to continue(y/n) -- "); scanf(" %c", &ch);}printf("\n\nTotal Memory Available -- %d", ms);printf("\n\n\tPROCESS\t\t MEMORY ALLOCATED "); for(i=0;i<n;i++)printf("\n \t%d\t\t%d",i+1,mp[i]); printf("\n\nTotal Memory Allocated is %d",ms-temp);printf("\nTotal External Fragmentation is %d",temp); getch();
Alert dont submit AI generated answer. Consider the following string of memory accesses. All of these access will miss, thus the hit rate will be zero.li t0, 0x1000sw t1, 0(t0) # 1sw t1, 0x10(t0) # 2sw t1, 0x20(t0) # 3sw t1, 0x30(t0) # 4sw t1, 0x40(t0) # 5What is the smallest offset greater than 0x10 that you can change #3 to that creates a conflict miss (specifically, evicting the data that was placed in the cache by instruction #2) in a 32-entry 4-word direct-mapped cache? Answer with the leading "0x".