14.1 A polymer solution was cooled very slowly until phase separation took place to give two phases in equilibrium. Subsequent analysis of the phases showed that the volume fractions of polymer in the phases were = 0.89 and 2 = 0.01, respectively. Using the equation for AG₁ given in Problem 10.1, together with the equilibrium condition AG=AG, calculate an estimate (two significant figures) of the Flory-Huggins polymer-solvent interaction param- eter for the conditions of phase separation.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter23: Polymeric Materials And Soft Condensed Matter
Section: Chapter Questions
Problem 14P
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14.1 A polymer solution was cooled very slowly until phase separation took place to give two
phases in equilibrium. Subsequent analysis of the phases showed that the volume fractions
of polymer in the phases were = 0.89 and 20.01, respectively. Using the equation for
AG₁ given in Problem 10.1, together with the equilibrium condition AG=AG, calculate an
estimate (two significant figures) of the Flory-Huggins polymer-solvent interaction param-
eter for the conditions of phase separation.
Transcribed Image Text:14.1 A polymer solution was cooled very slowly until phase separation took place to give two phases in equilibrium. Subsequent analysis of the phases showed that the volume fractions of polymer in the phases were = 0.89 and 20.01, respectively. Using the equation for AG₁ given in Problem 10.1, together with the equilibrium condition AG=AG, calculate an estimate (two significant figures) of the Flory-Huggins polymer-solvent interaction param- eter for the conditions of phase separation.
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