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15cт,Т-1о° TH159यीyAEeOTCos to as75desTetrisin16COs to-TsolsoLsn1Ceas 10tr sih Hs cotcos 10SintomgN

Question

We were given the diagram pictured and asked to solve for T1 and T2.

I did the work pictured but was told it is incorrect. Could you please tell me why?

15c
т,
Т
-1о°
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15c т, Т -1о°

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TH
159
यी
yA
EeOTCos to as75
des
Tetrisin16
COs to
-TsolsoLsn1
Ceas 10
tr sih Hs cot
cos 10
Sinto
mg
N
help_outline

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TH 159 यी yA EeOTCos to as75 des Tetrisin16 COs to -TsolsoLsn1 Ceas 10 tr sih Hs cot cos 10 Sinto mg N

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check_circleAnswer
Step 1
Tisin750
15
TI
Tasin100
75
10
T2 cos100
Ticos750
mg
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Tisin750 15 TI Tasin100 75 10 T2 cos100 Ticos750 mg

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Step 2

 System is in equilibrium.

From Newton’s second law:

Total force along X – axis = 0

Σ-0
T cos 75° 0
Ty cos 10
T cos 75°
T2
(i)
cos10
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Σ-0 T cos 75° 0 Ty cos 10 T cos 75° T2 (i) cos10

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Step 3

Total force along ...

ΣΗ-0
T sin 75 T sin 10° -mg 0
T sin 75°+T sin 10° = mg
Putting the value of T
T sin 750 cos 15x sin 10° = mg
cos 10°
cos 75°
x sin10° |= mg
Tsin 75°
cos10
mg
Ti
cos 75
xsin 10°
sin 75°
+
cos10
8.2 x 9.8
= 79.44 N
1.011562607
T 79.44 N
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ΣΗ-0 T sin 75 T sin 10° -mg 0 T sin 75°+T sin 10° = mg Putting the value of T T sin 750 cos 15x sin 10° = mg cos 10° cos 75° x sin10° |= mg Tsin 75° cos10 mg Ti cos 75 xsin 10° sin 75° + cos10 8.2 x 9.8 = 79.44 N 1.011562607 T 79.44 N

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