Question
Asked Feb 19, 2020
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2. Two blocks on separate level tables are connected by a spring as shown, How much is the spring stretched from its natural length if the system is at rest?

15kg
k = 35N/m
8 = 45°
18kg
Figure 2: Two blocks on separate level tables (both with a coefficient of static
friction of 4) are connected by a spring with k = 35N/m.
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15kg k = 35N/m 8 = 45° 18kg Figure 2: Two blocks on separate level tables (both with a coefficient of static friction of 4) are connected by a spring with k = 35N/m.

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Expert Answer

Step 1

Consider the tension in the spring to be T, N18 be the reaction of the block with 18 kg mass and f18 be the frictional force between the block and the table. Draw the free-body diagram of the block with the mass of 18 kg.

Mechanical Engineering homework question answer, step 1, image 1

Step 2

Write the expression of static equilibrium condition in the y-direction.

Mechanical Engineering homework question answer, step 2, image 1

Step 3

Understand that the blocks are lying at parallel surfaces to each other thus the spring also makes an angle of 45° with the horizontal.

Consider N15 to be the reaction of the block with 15 kg mass and f15 be the frictional force between the block and the table. Draw the free-body diagram of the block...

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