16.00 mL of a 0.125 M M(OH)2 solution is added to 25.00 mL of a 0.100 M HA solution in an acid-base neutralization reaction. M(OH)2 is a strong base where M2+ is a metal cation and OH– is the hydroxide ion. MM = 42.05 g/mol. HA is a strong acid where H+ is a proton and A– is an anion. MM = 65.23 g/mol.
16.00 mL of a 0.125 M M(OH)2 solution is added to 25.00 mL of a 0.100 M HA solution in an acid-base neutralization reaction. M(OH)2 is a strong base where M2+ is a metal cation and OH– is the hydroxide ion. MM = 42.05 g/mol. HA is a strong acid where H+ is a proton and A– is an anion. MM = 65.23 g/mol.
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16.00 mL of a 0.125 M M(OH)2 solution is added to 25.00 mL of a 0.100 M HA solution in an acid-base neutralization reaction.
- M(OH)2 is a strong base where M2+ is a metal cation and OH– is the hydroxide ion. MM = 42.05 g/mol.
- HA is a strong acid where H+ is a proton and A– is an anion. MM = 65.23 g/mol.
A. Write and balance the chemical equation for the double replacement reaction (no state symbols needed).
B. Determine the limiting reactant using moles of product and/or reactant.
C. Calculate the moles of excess reactant left over. Assume the reaction goes to completion.
D. Calculate the pH of the final solution. You can assume volumes are additive for simplicity.
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