Chapter 4.8, Problem 4.10CYU

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# A 25.0-mL sample of vinegar (which contains the weak acid acetic acid, CH3CO2H) requires 28.33 mL of a 0.953 M solution of NaOH for titration to the equivalence point. What is the mass of acetic acid (molar mass = 60.05 g/mol), in grams, in the vinegar sample, and what is the concentration of acetic acid in the vinegar?CH3CO2H(aq) + NaOH(aq) → NaCH3CO2(aq) + H2O(l)

Interpretation Introduction

Interpretation:

The mass of acetic acid and its concentration in the given 25.0mL sample of vinegar should be determined.

Concept introduction:

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.
• Concentrationofsubstance=Amountof substancevolumeofthesubstance
• Amountof substance=Concentrationofsubstance×volumeofthesubstance
Explanation

Balanced chemical equation for the given reaction is,

â€‚Â CH3CO2H(aq)â€‰+â€‰NaOH(aq)â†’â€‰NaCH3CO2(aq)+â€‰H2Oâ€‰(l)

The amount (moles) of NaOH available can be calculated by using the equation

Amountâ€‰ofÂ substanceâ€‰=â€‰Concentrationâ€‰ofâ€‰substanceâ€‰Ã—volumeâ€‰ofâ€‰theâ€‰substanceâ€‰

Amountâ€‰ofâ€‰NaOH =â€‰CNaOHÃ—VNaOH =â€‰0.953â€‰molâ€‰NaOHLâ€‰Ã—0.02833â€‰Lâ€‰NaOH =â€‰0.02700â€‰molâ€‰NaOH

The balanced equation for the reaction shows that 1â€‰mol of acetic acid requires 1â€‰mol of sodium hydroxide. This is the required stoichiometric factor to obtain the amount of acetic acid present.

Thus the amount of acetic acid can be calculated as follows,

â€‚Â 0.02700â€‰molâ€‰NaOHâ€‰Ã—â€‰1â€‰molâ€‰CH3CH2OH1â€‰molâ€‰NaOHâ€‰=â€‰0

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