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- Given the following data and the λmax determined in the previous questions, determine:1) the molar absorptivity of copper at λmax of cobalt 2) the molar absorptivity of copper at λmax of copper 3) the molar absorptivity of cobalt at λmax of cobalt 4) the molar absorptivity of copper at λmax of cobalt 5) the concentration of cobalt in mM 6) the concentration of copper in mM Copper concentration, mM λmax cobalt λmax copper 20.00 0.177 0.238 40.00 0.382 0.487 60.00 0.518 0.731 80.00 0.765 1.134 100.00 0.902 1.391 Cobalt concentration, mM λmax cobalt λmax copper 20.00 0.186 0.163 40.00 0.412 0.354 60.00 0.637 0.477 80.00 0.754 0.694 100.00 0.961 0.831 unknown, Abs at λmax cobalt 0.893 unknown, Abs at λmax copper 0.997What's the differences between two questions? Q1) How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations. -->Tap water 8Oz = 8 x 0.0296L = 0.2368L Hardness = 66.73ppm = 66.73mg/L CaCO3 1L has 66.73mg CaCO3 0.2368L has 66.73mg x 0.2368 = 15.8017mg MW of CaCO3 = 100g/mol MW of Ca = 40g/mol 100g CaCO3 has 40gf of Ca 15.8017mg CaCO3 has 40/100 x 15.8017mg Ca We would ingest 6.321mg of Ca. Q2) What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations. --> 66.73mg/1150mg x 100 = 5.80% My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it? CaCO3 = 100g/mol, Ca = 40g/mol 100g CaCO3 has 40g Ca. 66.73 CaCO3 has 40/100 x 66.73mg Ca Ca = 26.70mg 26.70mg/1150mg x 100 = 2.32%Both buret and volumetric pipet are mark TD or Ex. What does this mark mean? What are the major differences between the two and what are their applications?
- The gravimetric factor used to express CoCBr6·H20 in a sample that is finally weighed as PbClBr is choose below: FW PbClBr / 6 x FW CoCBr6·H20 FW CoCBr6·H20 / FW PbClBr FW CoCBr6·H20 / 6 x FW PbClBr 6 x FW PbClBr / FW CoCBr6·H205. If the label on the bottle lists the citric acid content as 1 g per serving with a serving size of 240 mL determine the percent error in the titration results. Express result with 2 significant figures.if 0.200 L of 0.24 M Ca(NO3)2 and 0.300 L of 0.043 M Na2CrO4 are mixed, what is the Qip? The Ksp for CaCrO4(s) = 7.1x10^-4
- Given the following data and the λmax determined in the previous questions, determine: 4) the molar absorptivity of cobalt at λmax of copper 5) the concentration of cobalt in mM 6) the concentration of copper in mM Copper concentration, mM λmax cobalt λmax copper 20.00 0.177 0.238 40.00 0.382 0.487 60.00 0.518 0.731 80.00 0.765 1.134 100.00 0.902 1.391 Cobalt concentration, mM λmax cobalt λmax copper 20.00 0.186 0.163 40.00 0.412 0.354 60.00 0.637 0.477 80.00 0.754 0.694 100.00 0.961 0.831 unknown, Abs at λmax cobalt 0.893 unknown, Abs at λmax copper 0.997Moles of HCl titrant = Excess Moles of NaOH analyte in solution (Moles NaOH added to acetylsalicylic acid) – (Excess Moles NaOH analyte in solution) = Moles NaOH reacted Moles NaOH reacted / 2 = Moles of acetylsalicylic acid The titration of the excess NaOH with HCl is a neutralization reaction: HCl (aq) + NaOH (aq) -> NaCl (aq)) + H2O (l) 2HCl (aq) + Na2CO3 (s) -> H2O (l) + CO2 (g) + 2NaCl (aq) Knowing the mass of sodium bicarbonate used, one can calculate the molesof sodium bicarbonate and the moles of HCl. With the volume readings from the burette and the moles of HClcalculated, the molarity of the HCl solution can be found. Na2CO3 is mixed with 25 mL of water in the titrated flask. final reading - Initial of HCl in burette is amount used. Show work A.) determine the concentration of the HCl solution from the data for the standardization of the HCl with the Na2CO3. B.)calculate the moles and mass of acetylsalicylic acid in each tablet (molar mass = 180.16 g/mol).…When drinking water is disinfected with chlorine, an undesired byproduct, chloroform (CHCl3), may form. Suppose a 70-kg person drinks 2 L of water every day for 70 years with a chloroform concentration of 0.08 mg/L (the drinking water standard). Potency factor for chloroform = 6.1 x 10-3 (mg/kg-day)-1 The upper-bound cancer risk for this individual. a. 0.545 b. 5.45x10-6 c. 5.45x10-4 d. 5.45x10-10 e. 14x10-6 If a city with 300,000 people in it also drinks the same amount water described in the above question, how many extra cancers per year would be expected? Assume the standard 70-year lifetime. a. 0.163 b. 1.63x10-4 c. 1.63x10-3 d. 1.63x10-6 e. 6x10-2