My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it? CaCO3 = 100g/mol, Ca = 40g/mol 100g CaCO3 has 40g Ca. 66.73 CaCO3 has 40/100 x 66.73mg Ca Ca = 26.70mg 26.70mg/1150mg x 100 = 2.32%

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter11: Intermolecular Forces And Liquids
Section11.6: Properties Of Liquids
Problem 1.2ACP
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What's the differences between two questions?

Q1) How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations.

-->Tap water 8Oz = 8 x 0.0296L = 0.2368L

 

Hardness = 66.73ppm = 66.73mg/L CaCO3

1L has 66.73mg CaCO3

0.2368L has 66.73mg x 0.2368 = 15.8017mg

 

MW of CaCO3 = 100g/mol

MW of Ca = 40g/mol

100g CaCO3 has 40gf of Ca

15.8017mg CaCO3 has 40/100 x 15.8017mg Ca

 

We would ingest 6.321mg of Ca.

 

Q2) What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations.

--> 66.73mg/1150mg x 100 = 5.80%

 

 

My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it?

CaCO3 = 100g/mol, Ca = 40g/mol

100g CaCO3 has 40g Ca.

66.73 CaCO3 has 40/100 x 66.73mg Ca

Ca = 26.70mg

26.70mg/1150mg x 100 = 2.32%

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