1621.56 1243.52 1232.84 815.04 658.50 1572.37 1476.52 1464.39 1339.50 1147.64 778.68 1098.78 1421.27 615.81 1292.55 1054.41 748.47 3456.02 3202.74 1674.07 847.95 3332-25 2542.13 2161.02

Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter17: Electrochemistry
Section: Chapter Questions
Problem 45E: If a sample of iron and a sample of zinc come into contact, the zinc corrodes but the iron does not....
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Based on the experiment- Synthesis of Iodosalicylamide – An Electrophilic Aromatic
Substitution (a derivative of benzene, salicylamide was used and substituted an iodine atom onto the ring; the ring is the nucleophile while the atom/molecule that is being substituted onto the ring has an
electrophilic character) 
Please I need help with this QUESTION:  Draw the structure of the final product(s) based on the ATTACHED IR analysis. Also label the signals (both the frequency and molecular motion) that help determine the final product(s). Thanks in advance

1000
1621.56
1243.52 1232.84
815.04
658.50
1572.37
1476.52 1464.39
1339.50
1147.64
778.68
1098.78
1421.27
1292.55
615.81
1054.41
748.47
3456.02
3202.74
1674.07
847.95
3332-25
2542.13
2161.02
Transcribed Image Text:1000 1621.56 1243.52 1232.84 815.04 658.50 1572.37 1476.52 1464.39 1339.50 1147.64 778.68 1098.78 1421.27 1292.55 615.81 1054.41 748.47 3456.02 3202.74 1674.07 847.95 3332-25 2542.13 2161.02
substituent on the ring. As far as the exact location of the substitution, you'll need to predict
based on your knowledge of the types of activating/deactivating groups already substituted on
salicylamide.
NH₂
OH
1.) Nal, NaOCI, CH₂CH₂OH
2.) Na₂S₂O3. CI
NH₂
OH
As a quick reference, the mechanism for the electrophilic aromatic substitution is shown below.
The electrophile, It, is generated from 12. The nucleophile, the pi electrons of the ring, attacks I*
and loses aromaticity, forming a sigma complex. This sigma complex is a resonance stabilized
carbocation intermediate. The ring will then regain aromaticity once it is deprotonated by a
base.
Transcribed Image Text:substituent on the ring. As far as the exact location of the substitution, you'll need to predict based on your knowledge of the types of activating/deactivating groups already substituted on salicylamide. NH₂ OH 1.) Nal, NaOCI, CH₂CH₂OH 2.) Na₂S₂O3. CI NH₂ OH As a quick reference, the mechanism for the electrophilic aromatic substitution is shown below. The electrophile, It, is generated from 12. The nucleophile, the pi electrons of the ring, attacks I* and loses aromaticity, forming a sigma complex. This sigma complex is a resonance stabilized carbocation intermediate. The ring will then regain aromaticity once it is deprotonated by a base.
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