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Social Science17. 1/4 points| Previous Answers SerCP11 16.5.P.033.MI.points 1Previous Answers SercP11 16.5 P.033 MI..My Notes Ask Your TeacherAn air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm, separated by a distance of 1.90 mm. If a 15.2-V potential difference is applied to these platescalculate the following.(a) the electric field between the platesmagnitudedirection from the positive plate to the negative platekV/m(b) the capacitancePF(c) the charge on each platepC
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17. 1/4 points| Previous Answers SerCP11 16.5.P.033.MI. points 1Previous Answers SercP11 16.5 P.033 MI.. My Notes Ask Your Teacher An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm, separated by a distance of 1.90 mm. If a 15.2-V potential difference is applied to these plates calculate the following. (a) the electric field between the plates magnitude direction from the positive plate to the negative plate kV/m (b) the capacitance PF (c) the charge on each plate pC
Expert Answer
Given: Area(A) = 7.60 cm2 = 0.00076m2
distance(d) = 1.90mm = 0.0019m
Potential difference = 15.2V
Find: (a) Electric field(E) = ?
(b) the capacitance(C) = ?
(c) the charge on each plate(Q) = ?
(a) to calculate electric field, use the formula as follows:
(b) to calculate capacitance, us...
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