17. If a 575-volt three-phase motor originally connected in 3-parallel △ is reconnected in 5-parallel Y, the new voltage is B. 598 volts. C. 501 volts. D. 747 volts.
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17. If a 575-volt three-phase motor originally connected in 3-parallel △ is reconnected in 5-parallel Y, the
new voltage is
B. 598 volts.
C. 501 volts.
D. 747 volts.
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- 7. If a 575-volt three-phase motor originally connected in 3-parallel △ is reconnected in 5-parallel Y, thenew voltage isA. 501 volts.B. 794 volts.C. 598 volts.D. 747 volts.A three-phase alternator of 4 poles and 60 HZ, connected in star of 100 KVA and 1100 volts is tested for OCC, SCC and winding resistance, giving the following data: Based on the above data, obtain: a) - The equivalent circuit per phase of the alternator b) - Operating speed c) - If it is synchronized with a power system whose frequency is 60 Hz and the alternator has a Sp=5 kW/Hz and its speed at the moment of synchronization is 1860 rpm, what power will it deliver? d) - What will be your internal voltage generated if you feed a load with forward PF of 0.9 and you are at 80% of your load? e) - For the case of item d), what is the reactive power delivered or consumed?3-phase,50 Hz, delta connected generator, its stator winding having 12sninai ns pole pair and 6 conductors in each, if the total air gap flux is 160mwb. Find the terminal voltage. The prime mover speed is 750rpm.
- The data obtained in the idling test performed on a three-phase star-connected asynchronous motor; It is 1200V, 5500W, 9.5A. The data obtained in the short circuit experiment on the same motor is 250V,It is 14500W and 100A. For the case where the slip of the motor is 5%, create the approximate equivalent circuit of the motor (L type equivalent circuit), draw the equivalent circuit, find the values of the circuit elements and MUST AND MUST write them ON THE EQUIVALENT CIRCUIT. R and X values will be used in circuit elements, not Z.A 3-phase, 20 MVA, 1IkV, star-connected generator is protected by the current balancing system of protection. If the ratio of the current transformer is 1,200/5, the minimum operating current of the relay is 0.75 ampere and the neutral point earthing resistance is 6 ohms, calculate, the percentage of each phase of the stator winding which is unprotected against earth faults when the machine is operating at normal voltage. Show quantitatively. the effect of varying neutral earthing resistance [say R = 3 ohm and 12 ohm].A 3-phase, 50 Hz,2000 kVA, 2300 volt alternator gives a short circuit current of 600 A for a certain field excitation. For the same excitation, the open circuit voltage was 900 volts. The resistance between pair of terminals was 0.12 ohm. B)If the generator is deltaconnected, -Determine the full load regulation at 0.80 lagging pf. -Determine the full load regulation at unity pf
- S:06) a) A three-phase motor with delta connection is supplied as in Figure below. Determine the Voltage Unbalance Factor of the motor b) Proof that the percentage of voltage unbalance determination using maximum deviation method is bigger than the symmetrical components method for problem in (a).The effective resistance of a 2200 V, 50 Hz, 440 KVA, 1 -phase alternator is 0.5 ohm. On short-circuit, a field current of 40 A gives the full load current of 200 AS. The electromotive force on open-circuits with same field excitation is 1160 V. Then the synchronous impedance and reactance is _______ ohm and _______ ohm respectively.A 3-Phase 10Kva, 400 V, 50Hz star connected alternator supplies a rated load at 0.8 power factor lagging. If the armature resistance per phase is 0.5Ჲ and the synchronous reactance is 10Ჲ, using the e.m.f method, estimate the alternator’s voltage regulation
- Consider a three-phase 13.8 kV, 25-MVA, Y-connected synchronous generator whose three-phase short-circuit losses are 52.8 kW at rated armature current. Calculate its armature resistance per phase. a-0.16 Ohm b-0.016 Ohm -1.016 Ohm: d- 603.2 A e-0.7 Ohm.A three-phase, 250 MVA, 16 kV rated synchronous generator is feeding into an infinite bus bar at 15 kV. The generator has a synchronous reactance of 1.62 pu. It is found that the machine excitation and mechanical power input are adjusted to give E = 24 kV and power angle δ = 30◦. a) Determine the line current and active and reactive power fed to the generator terminal. b) The mechanical power input to the generator is increased by 20% from that in part (a) but its excitation is not changed. Find the new line current and power factor. c) With reference to part (a) current is to be reduced by 20% at the same power factor by adjusting mechanical power input to the generator and its excitation. Determine E, angle δand mechanical power input.36.A 1000-kVA, 11-kV three-phase wye-connected synchronous generator supplies a 600-kW, 0.8 leading of load. The synchronous reactance is 24 Ω per phase and the armature resistance is negligible. Calculate the voltage regulation.