2 3 4 3H 2H 2H 2H 1H 12 16 PPM Peak Splitting 1 singlet triplet 3 quintet 4 sextet triplet Shown above is the 'H-NMR spectrum of a compound with the formula C5 H10 O2. Choose from the constitutional isomers below to assign a structure to this spectrum.
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A: option C
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- A chiral hydrocarbon X exhibits a molecular ion at 82 in its mass spectrum. The IR spectrum of X shows peaks at 3300, 3000–2850, and 2250 cm-1. Propose a structure for X.Compound C has the molecular formula of C6H12O2 with the following IR data. The mass and NMR (1H and 13C NMR) spectra are shown below. IR (cm-1): 2800, 2950, 1710 and 1120 cm-1An unknown compound C (molecular formula C4H8O3) exhibits IR absorptions at 3600−2500 and 1734 cm−1, as well as the following 1H NMR spectrum. What is the structure of C?
- A) compound X has the formula C8H15OCl. Calculate the double bond equivalents in this molecule B) the proton decoupled 13C NMR Spectrum for compound X has 6 signals, with one signal above 100 ppm. What does this indicate about the symmetry in compound XIdentify the structures of isomers H and I (molecular formula C8H11N).a.) Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and1497 cm−1 b.) Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and1492 cm−1Treatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppm
- Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.Propose possible structures consistent with each set of data. Assume each compound has an sp3 hybridized C – H absorption in its IR spectrum, and that other major IR absorptions above 1500 cm are listed. a. a compound having a molecular ion at 72 and an absorption in its IR spectrum at 1725 cm−1 b. a compound having a molecular ion at 55 and an absorption in its IR spectrum at ~2250 cm−1 c. a compound having a molecular ion of 74 and an absorption in its IR spectrum at 3600–3200 cm−1Propose possible structures consistent with each set of data. Assume each compound has an sp3 hybridized C—H absorption in its IR spectrum, and that other major IR absorptions above 1500 cm−1 are listed. a.a compound having a molecular ion at 72 and an absorption in its IR spectrum at 1725 cm−1 b. a compound having a molecular ion at 55 and an absorption in its IR spectrum at −2250 cm−1 c.a compound having a molecular ion at 74 and an absorption in its IR spectrum at 3600−3200 cm−1
- What is the structure of a compound of molecular formula C10H14O2 that shows a strong IR absorption at 3150–2850 cm-1 and gives the following 1H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?Identify the structures of D and E, isomers of molecular formula C6H12O2, from their IR and 1H NMR data. Signals at 1.35 and 1.60 ppm in the 1H NMR spectrum of D and 1.90 ppm in the 1H NMR spectrum of Eare multiplets.a. IR absorption for D at 1743 cm−1b. IR absorption for E at 1746 cm−1What is the structure of the compound with the formula C5H12O, if it has a strong broad IR signal centered near 3330 cm-2, and the 1H-NMR spectrum is: 0.91 ppm (3H triplet) 1.19 ppm (6H singlet) 1.50 ppm (2H quartet) 2.24 ppm (1H singlet)