A bar of length 5 m is subjected to an axial tensile out of 100 KN The bar is 25 min diameter for 2 mof its length 30 mm diameter for I mor its length, and 20 mm diameter for the remaining 2 m of its length, Taking E= 2 x 10' Calculate the total increase in length of the bur. 2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m ofits length. Taking E = 2 x 10$ N/mm2. Calculate the total increase in length of the bar.(Total increase in length = dl = 5.9 mm)

According to the given information we have a bar of 5 m to an axial load of 100 Kn the bar is 25 mm…

2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2 m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of its length. Taking E = 2 x 10° N/mm2. Calculate the total increase in length of the bar. %3D (Total increase in length = dl = 5.9 mm)

2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2 m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of its length. Taking E = 2 x 10° N/mm2. Calculate the total increase in length of the bar. %3D (Total increase in length = dl = 5.9 mm)

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.2.7P: Rigid bar ACB is supported by an elastic circular strut DC having an outer diameter of 15 in. and...

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