2\ Answer T for true statements or F for false ones: 1. Intact rock: solid rock sample containing cracks on eye naked. 2. Rock Mass: contains rock samples and crack surfaces on eye naked. 3. The rock sample will break if the applied force is vertical and associated with shear. 4. Unit weight (Y) = gm./cm³. 5. Void Ratio (e) = Vs/Vv. 6. In point load test if the rock is fresh, ot=5 * Is (50) 7. Brazilian Test provides tensile strength values closer to reality than Point Load Test. 8. Schmidt Hammer Test gives direct values for strength. 9. As more the surface is rough its strength for slipping decreases. 10.Fracture Intercept is the measured distance between irregular fractures %3D

2\ Answer T for true statements or F for false ones: 1. Intact rock: solid rock sample containing cracks on eye naked. 2. Rock Mass: contains rock samples and crack surfaces on eye naked. 3. The rock sample will break if the applied force is vertical and associated with shear. 4. Unit weight (Y) = gm./cm³. 5. Void Ratio (e) = Vs/Vv. 6. In point load test if the rock is fresh, ot=5 * Is (50) 7. Brazilian Test provides tensile strength values closer to reality than Point Load Test. 8. Schmidt Hammer Test gives direct values for strength. 9. As more the surface is rough its strength for slipping decreases. 10.Fracture Intercept is the measured distance between irregular fractures %3D

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter14: Sheet-pile Walls

Section: Chapter Questions

Problem 14.13P

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7. Shear strength of intact rocks determined by 8. Deformation parameters Test. are and
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Q#5: From the Tri –axial test, determine the effective normal stress on the plane of Maximum shear stress. Explain why the shear failure occurred along the plane with angle 54.73 and not along the plane of maximum shear stress. Take σ’1 = 552, σ’3 = 276, ø’ = 19.45?
50 MPa Oc ON tan ф 20 + + -20 MPa 50 MPа 100 MPа O = 90 –20 -50 MPа
Q#5: From the Tri –axial test, determine the effective normal stress on the plane of Maximum shear stress. Explain why the shear failure occurred along the plane with angle 54.73 and not along the plane of maximum shear stress. Take σ’1 = 552, σ’3 = 276, ø’ = 19.45? Find σ’ = ? τf = ? τ: ?
Q3\ Fill in the blanks with appropriate items: 1. Static force classified according to action into: 2. Physical properties of rocks are controlled by: 3. Strength value is amount of stress at -- 4. Point- Load Index (Is) = ----- 5. Point-load index for sample of 50 mm Diameter = 6. In point load test: Average ot= 7. Shear strength of intact rocks determined by 8. Deformation parameters are ---- 9. The friction strength formula of a discontinuity surface is: 10.At mountainous areas, RQD can be computed by equation: and --------and ------ Test. and --
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