be immersed and cell of the follow type is produced:Ag|AGCLHC(aq)\glass|unknownsolution|KCl|Hg,Cl,(s)Balancing Oxidation-Reduction Equations:Ex: HNO3 + H2S → NO +S + H20Sol:3e- +N+5 → N+2]×2= 6e- + 2N*5S-2 S° + 2e-]x3 = 3S-2 3S° + 6e-ReductionOxidation- 2N+28H2602HNO, +3H,S → 2NO + 3S + 4H,0 81, 602N+5 + 3S-2 –→2N+2 + 35°+6Ex: KMN0, + KCl + H,šö,Sol: + +X-8-o- MNSO, + K,S0, + H¿0 + Cl,X+6-8=0X= +210e- + 2Mn+7 –2Mn+2 RedAsid5e-+ Mn+7 – Mn+2 =201- Cl2 + 2e¯ = 10Cl- 5Cl, + 10e-2KMN0, + 10KCI + 8H2S0, → 2MNSO, + 5C12 + 8H20+7252 Mn+ 10 c1> 2 Mn?2K Mn nkcl2 .Sa I Mnsout 5cl2+Solve the question with suchstepsThanks Balancing osidation-reductionEquationa2 HW:Zn + NANO, + NAOHNazZn02 + NH3 + H2O

Its a redox reaction.and the reaction is taking place in basic medium. The rule for balancing in…

Answered: 2 HW:Zn + NANO, + NaOH NazZn02 + NH3 +…

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Chemistry

2 HW:Zn + NANO, + NaOH NazZn02 + NH3 + H2O

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter18: Introduction To Electrochemistry

Section: Chapter Questions

Problem 18.27QAP

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

100%

be immersed and cell of the follow type is produced:
Ag|AGCLHC(aq)\glass|unknownsolution|KCl|Hg,Cl,
(s)
Balancing Oxidation-Reduction Equations:
Ex: HNO3 + H2S → NO +S + H20
Sol:
3e- +N+5 → N+2]×2= 6e- + 2N*5
S-2 S° + 2e-]x3 = 3S-2 3S° + 6e-
Reduction
Oxidation
- 2N+2
8H260
2HNO, +3H,S → 2NO + 3S + 4H,0 81, 60
2N+5 + 3S-2 –→
2N+2 + 35°
+6
Ex: KMN0, + KCl + H,šö,
Sol: + +X-8-o
- MNSO, + K,S0, + H¿0 + Cl,
X+6-8=0
X= +2
10e- + 2Mn+7 –
2Mn+2 Red
Asid
5e-+ Mn+7 – Mn+2 =
201- Cl2 + 2e¯ = 10Cl- 5Cl, + 10e-
2KMN0, + 10KCI + 8H2S0, → 2MNSO, + 5C12 + 8H20
+7
25
2 Mn+ 10 c1
> 2 Mn?
2K Mn nkcl
2 .Sa I Mnsout 5cl2+
Solve the question with such
steps
Thanks

Balancing osidation-reduction
Equationa
2 HW:Zn + NANO, + NAOH
NazZn02 + NH3 + H2O

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