2 Random variables, X, Y, etc. form a vector space (i.e. they satisfy properties such as closure under addition and scalar multiplication). Furthermore we can define an inner product between random variables as (X,Y) = E[XY] (i.e. the expectation of the random variable Z = XY) (a) Use the Cauchy-Schwarz inequality to show that Cov(X,Y)2 < Var(X) Var(Y) hence show that the Pearson correlation is between -1 and 1.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.2: Linear Independence, Basis, And Dimension
Problem 43EQ
icon
Related questions
Question
100%
Plz solve this now in one hour and get thumb up plz
2 Random variables, X, Y, etc. form a vector space (i.e. they satisfy properties
such as closure under addition and scalar multiplication). Furthermore we can define
an inner product between random variables as
(X,Y) = E[XY]
(i.e. the expectation of the random variable Z = XY)
(a) Use the Cauchy-Schwarz inequality to show that
Cov(X,Y)2 < Var(X) Var(Y)
hence show that the Pearson correlation is between -1 and 1.
Transcribed Image Text:2 Random variables, X, Y, etc. form a vector space (i.e. they satisfy properties such as closure under addition and scalar multiplication). Furthermore we can define an inner product between random variables as (X,Y) = E[XY] (i.e. the expectation of the random variable Z = XY) (a) Use the Cauchy-Schwarz inequality to show that Cov(X,Y)2 < Var(X) Var(Y) hence show that the Pearson correlation is between -1 and 1.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer