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- H2O2(l) deltaG=-120.4 H2O(l) deltaG=-237.1 O2 (g) deltaG=0125 kg of coal contains about 7.0 % sulfur, by complete burning, the gases were circulated in a wet scrubber containing 25 kg of CaCO3 to convert SO2 evolved by complete burning to CaSO4. Is the amount of CaCO3 enough to absorb all SO2 or not? If not, how many molecules of SO2 will escape from the wet scrubber?What weight Fe2O3 (FW = 159.69) can be obtained from 2.63 g of Fe3O4 (FW = 231.53) by gravimetric method *
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- 5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?Vanadic ion, V3+, forms green salts and is a good reducingagent, being itself changed in neutral solutions to thenearly colorless ion V(OH)4+. Suppose that 15.0 mL of a0.200-M solution of vanadic sulfate, V2(SO4)3, was neededto reduce completely a 0.540-g sample of an unknownsubstance X. If each molecule of X accepted just oneelectron, what is the molecular weight of X? Suppose thateach molecule of X accepted three electrons; what wouldbe the molecular weight of X then?Consider a mixture of the two solids, BaCl2 ∙ 2H2O (FM 244.26) and KCl (FM 74.551). When the mixture is heated to 160°C for 1 h, the water of crystallization is driven off: BaCl2 ∙ 2H2O(s) BaCl2(s) + 2H2O(g) A sample originally weighing 1.7839 g weighed 1.5623 g after heating. Calculate wt% Ba, K, and Cl in the original sample. (Hint: The mass loss tells how much water was lost, which tells how much BaCl2 ∙ 2H2O was present. The remainder of the sample is KCl.)