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- The p-value for the above problem is < 0.0001. Which of the following is a correct conclusion? There is not enough evidence that all of the proportions of European football players who take magnesium in topical, pill, and powder form are the same as reported by the football agency. There is strong evidence that all of the proportions of European football players who take magnesium in topical, pill, and powder form are different than reported by the football agency. There is strong evidence that all of the proportions of European football players who take magnesium in topical, pill, and powder form are the same as reported by the football agency. There is strong evidence that at least one of the proportion of European football players who take magnesium in topical, pill, and powder form is different than reported by the football agency. There is not enough evidence that at least one of the proportion of European football players who take magnesium in topical, pill, and…2. Consider a study where students are measured on whether they had an internship during their time at WKU (Y/N) and whether they had a job at graduation (Y/N). If we wanted to test whether having an internship was associated with having a job at graduation (i.e., internship holders were more likely to have jobs), why would the chi-square test be inappropriate for this hypothesis? How should we analyze our data?If the test of H0: = 19 against Ha: ≠ 19 based on an SRS of 15 observations from a Normal populationproduces the statistic of t = –1.75. The P-value is
- Serum nitrite concentrations (in μmol/L) were compared between a group of unmedicated HIV+ subjects (n =7) and a control group (n = 10). The HIV+ distribution is strongly skewed.a) Use a Wilcoxon-Mann-Whitney U test to determine if there is convincing evidence at α = 0.05 thatserum nitrite levels differ between the two populations. b) What would have been the U test p-value if researchers had instead hypothesized that serum nitriteconcentrations would tend to be larger in the HIV+ population? HIV+ Control 0.266 0.167 0.269 0.201 0.299 0.205 0.335 0.232 0.503 0.234 0.846 0.260 0.946 0.268 0.288 0.301 0.305Serum nitrite concentrations (in μmol/L) were compared between a group of unmedicated HIV+ subjects (n =7) and a control group (n = 10). The HIV+ distribution is strongly skewed. a) Use a Wilcoxon-Mann-Whitney U test to determine if there is convincing evidence at α = 0.05 thatserum nitrite levels differ between the two populations. b) What would have been the U test p-value if researchers had instead hypothesized that serum nitriteconcentrations would tend to be larger in the HIV+ population?Suppose we take a sample of 2,500 blood donors from a population for which 50% (0.5) have type O+ blood. (a) Into what range of possible values should the sample proportion fall 95% of the time, according to the Empirical Rule? to (b) If the sample included only 625 donors instead of 2,500, would the range of possible sample proportions be wider, more narrow, or the same as with a sample of 2,500 donors? Explain your answer, and explain why it makes intuitive sense. The range would be with 625 donors compared to a sample of 2,500 donors since the standard deviation of the sampling distribution would be . This makes intuitive sense because if fewer donors are included in the sample, the proportion will be reliable as an estimate of the proportion.
- A random sample of n = 25 individuals is selected from a population with μ = 20, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M = 22.2 with SS = 384. a. How much difference is there between the mean for the treated sample and the mean for the original population? (Note: In a hypothesis test, this value forms the numerator of the t statistic.) c. Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with α = .05.To evaluate the effect of a treatment, a sample is obtained from a population with a mean of μ = 25, and the treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be M= 27.4 with SS = 64. If the sample consists of 9 individuals, what is the t statistic, and are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with α = .05?In the nation of Gondor, the EPA requires that half the new cars sold will meet a certain particulate emission standard a year later. A sample of 64 one-year-old cars revealed that only 20 met the particulate emission standard. What is the test statistic to see whether the proportion is below the requirement?
- A sample of n=10,000 (x, y) pairs resulted in r= .022. Test H0: p=0 versus Ha: p=? 0 at significance level .05. Is the result statistically significant? Comment on the practical significance of your analysis.A random sample of n= 4 individuals is selected from a population with μ = 35, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M = 40.1 with SS = 48. How much difference is there between the mean for the treated sample and the mean for the original population? (Note: In a hypothesis test, this value forms the numerator of the t statistic.) If there is no treatment effect, how much difference is expected between the sample mean and its population mean? That is, find the standard error for M. (Note: In a hypothesis test, this value is the denominator of the t statistic.) Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with α = .05.The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…