2. Copper is extracted from chalconite (Cu2S) via the following reactions: reaction a: 2 Cu2S + 3 02 -- > 2 Cu20 + 2 SO2 reaction b: Cu20 + C --> 2 Cu + CO Suppose there are 0.15 mol Cu2S , 0.15 mol 02 and 0.15 mol C are used and that both reactions are completed. How many moles of copper are then obtained? asnwer; 0.20mol

2. Copper is extracted from chalconite (Cu2S) via the following reactions: reaction a: 2 Cu2S + 3 02 -- > 2 Cu20 + 2 SO2 reaction b: Cu20 + C --> 2 Cu + CO Suppose there are 0.15 mol Cu2S , 0.15 mol 02 and 0.15 mol C are used and that both reactions are completed. How many moles of copper are then obtained? asnwer; 0.20mol

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

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Chapter13: Isolation Of Eugenol From Clov

Section: Chapter Questions

Problem 9Q

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A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed of only N2 and O2 with a molar ratio of 3.76:1.00, and the N2 remains unreacted. In addition to the water produced, the fuels C is completely combusted to CO2 and its sulfur content is converted to SO2. In order to evaluate gases emitted at the exhaust stacks for environmental regulation purposes, the nitrogen supplied with the air must also be included in the balanced reactions. a Including the N2 supplied m the air, write a balanced combustion equation for the complex fuel assuming 100% stoichiometric combustion (i.e., when there is no excess oxygen in the products and the only C-containing product is CO2). Except in the case of N2, use only integer coefficients. b Including N2 supplied in the air, write a balanced combustion equation for the complex fuel assuming 120% stoichiometric combustion (i.e., when excess oxygen is present in the products and the only C-containing product is CO2). Except in the case of use only integer coefficients c Calculate the minimum mass (in kg) of air required to completely combust 1700 kg of C11H7S. d Calculate the air/fuel mass ratio, assuming 100% stoichiometric combustion. e Calculate the air/fuel mass ratio, assuming 120% stoichiometric combustion.
For the following reaction: 5Ca + V2O5 --> 5CaO + 2V In one process 5 moñ of V2O5 react with 3 mol of acá. Calculate the theoretical yield of V in the unit of mol.
0.004 C8H7NO3, 15mL ethanol, 0.002mol NaBH4 was used. HCl was used to acidify. It was then extracted with ether. Then it was dried and a mass of 0.32g was obtained. What is the balanced equation of this synthesis, and what is the limiting reagent?
The hydrated salt, MY3·xH2O, was heated strongly in a crucible to remove all the watermolecules of crystallization.The data are for this experiment are given in the table below.Mass of empty crucible and cover 29.73 gMass of crucible, cover, and hydrated salt 32.72 gMass of crucible, cover, and anhydrous salt 31.52 gMolar mass of anhydrous salt 241.88 g/mol(i) Calculate the % composition by mass of water in the hydrated salt.(ii) Determine the value of x.(iii) M is in Period 4 of the Periodic Table of the Elements.If Y = NO3–, identify the element M.(iv) What is the name of this hydrated salt? ___
A chemist carries out the reaction below and obtains 3.45g of iron Fe (Fe, MW=55.845g/mol). Fill in the blanks below to determine the percent yield of the reaction when 8.30g of Fe2O3 (MW= 159.69g/mol) and 3.50g of CO (MW=28.01G/mol)were used in the reaction. Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g) Note that for two of the blanks, will be the same answer. 1. What would be the mass in grams of Fe produced based on the mass of Fe2O3 used? answer: (blank) 2. What would be the mass in grams of Fe produced based on the mass of CO used? answer: (blank) 3. What is the theoretical yield of Fe in grams? answer: (blank) 4. What is the limiting reagent? Enter the formula of compound. answer: (blank) 5. What is the percent yield of this reaction? answer: (blank)
Write the empirical formula for the hydrated KAl(SO4)2, based on moles of anhydrous KSI(SO4)2= 0.046 mol molar mass of H2O= 18g/ mol moles of H2O= 0.0444mol ratio pf moles H20 to moles of anhydrous KAI(SO4)2= 9.65/1 . Show all work including units. Hint: if the ratio of moles of H2O to moles of anhydrous KAl(SO4)2 was 4, then the empirical formula would be: KAl(SO4)2•4H2O.
A sample of an industrial waste water is analyzed and found to contain 16.5ppb Fe2+. How many grams of iron could be recovered from 1.81×103 kg of this waste water? Answer:_______ grams Fe
Given Active Ingredient: precipitated sulfur (ointment) Raw Materials: 500 g calcium polysulphide and 1.5 kg hydrochloric acid Actual Yield: 343.4g precipitated sulfur Formulation: 250 mg per jar Dosage form: Ointment packaging:100 jars per box Synthesis and Packaging (Need answer)- Balanced Chemical Equation:- % composition by mass of each compound:- Mass to Mass Stoichiometry Calculation:- Limiting Reagent:- Excess Reagent:- Amount (g) in excess: % Yield:- Number of dosage form and packaging that can be produced from stoichiometric solution:
a piece of zn metal (25)g reacts with 100ml of a 2m hcl solution to form zncl2 and h2 gas. What mass of H2 will be produced if the limitng reagant is fully consumed? How many moles of limiting reagant remains after the reatioin?
Excess HCl reacts with Be to produce 50cm3 of hydrogen gas at 20 °C and 1.08x104 Pa. The equation for this reaction is shown below: Be +2HCl=BeCl2+H2 a) calculate the moles of hydrogen gas given off b)calculate the mass of Be that was required for this reaction
Potassium chromate, a bright yellow solid, is produced by the reaction of solid chromium ore (FeCr2O4) with solid potassium carbonate and gaseous oxygen at high temperatures. The other products of the reaction are solid iron (III) oxide and gaseous carbon dioxide. If you use 169.0g of chromium ore, 298.0g of potassium carbonate and 75.00g of oxygen in a sealed reaction vessel, what is the limiting reagent? Give the theoretical yield of potassium chromate, in grams, for each one.
2N2(g) + 3O2(g) ® 2N2O3(g) DH°rxn = +86.6 kJ 1. When 12.0 moles of N2 react, the reaction heat is ____________ kJ 2. To make +552 kJ of reaction heat, _________ moles of O2 must react. 3. To make +24 kJ of reaction heat, a count of ________________ N2O3 molecules must form.

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