2. For each of the following set of binary numbers, determine the logic states at each point in the logic symbol of 7485 4-bit comparator. a) P3 P2 P, Po=1100 Q3 Q2 Qı Qo=1010

Electric Motor Control
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Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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2. For each of the following set of binary numbers, determine the logic states at each point in
the logic symbol of 7485 4-bit comparator.
a) P3 P2 P, Po=1100
Q3 Q2 Qı Qo=1010
Transcribed Image Text:2. For each of the following set of binary numbers, determine the logic states at each point in the logic symbol of 7485 4-bit comparator. a) P3 P2 P, Po=1100 Q3 Q2 Qı Qo=1010
Expert Solution
Step 1

A comparator is a device which used to signifying which of two binary numbers have greater magnitude. Now, the steps of comparing the two 4-bit numbers P= P3P2P1P0 and Q=Q3Q2Q1Q0 is as following.

First, compare the most significant bit P3 and Q3 of the numbers. Let P3 =1 and Q3=0, than P3>Q3

 However the remaining bit required to compare. If P3 =0 and Q3=1, than P3<Q3

If both P3 and Q3 bit are equal then it moves to 2nd step. From the given question the MSBs of P and Q is equal that is 1 hence, it moves to 2nd stage of comparator.

Step 2

Now, compare the next significant bit P2 and Q2 of the given numbers. Let P2 =1 and Q2=0, than P2>Q2

 However the remaining bit required to compare. If P2 =0 and Q2=1, than P2<Q2

If both P2 and Q2 bit are equal then it moves to 3rd step. From the given question the 2nd bit of P and Q has P2>Q2 that is 1>0 hence, it moves from the comparator results shown P>Q.

Similarly the comparison proceeds if the bits coincides.

 

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