I need answer in handwritten 2. For the system described by the differential cquation:d'y(1),d'y(1), 3 dy(0)+ y(1) =+ u(t), The transfer function is derived todtdu(t)+3dt'dt?dtbe:a)U(s)%3Dsa +3s +35+ 1(s)b)U(:)S+135+35+1(:)c)U(:)S+3%3D(:)S+1d)U(?)%3D

Answered: Image /qna-images/answer/157230d1-b458-4678-84b0-319085750416.jpg

2. For the system described by the differential cquation: d'y(1),d'y(1), 3 dy(1) + y(1) = + u(t), The transfer function is derived to dt +3 du(t) +3- + y(t) = dt dt' dt? be: a) e) U(s) %3D s+3s+35+1 S+1 b) U(;) %3D 35+35+1 S+3 c) U(:) %3D s+3s +35+3 Y(:) d) U(?) S+1 %3D

2. For the system described by the differential cquation: d'y(1),d'y(1), 3 dy(1) + y(1) = + u(t), The transfer function is derived to dt +3 du(t) +3- + y(t) = dt dt' dt? be: a) e) U(s) %3D s+3s+35+1 S+1 b) U(;) %3D 35+35+1 S+3 c) U(:) %3D s+3s +35+3 Y(:) d) U(?) S+1 %3D

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter4: Numerical Analysis Of Heat Conduction

Section: Chapter Questions

Problem 4.6P

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Engineering Drawing

Technical drawing has been around since ancient times. As in the ancient Renaissance, complicated drawings were created, including Leonardo da Vinci's drawing. Modern engineering drawing, including its specific orthographic projection with scale conventions, began in Europe (France) during the early stages of Industrialization. L.T. C. Rolt also made some of Marc's drawings for its block-making machinery (in 1799) that also may have contributed significantly to British engineering technology. Since he learned the art of presenting three-dimensional(3D) items in a two-dimensional(2D) plane, as we now term mechanical drawing. 

Question

I need answer in handwritten

2. For the system described by the differential cquation:
d'y(1),d'y(1), 3 dy(0)+ y(1) =
+ u(t), The transfer function is derived to
dt
du(t)
+3
dt'
dt?
dt
be:
a)
U(s)
%3D
sa +3s +35+ 1
(s)
b)
U(:)
S+1
35+35+1
(:)
c)
U(:)
S+3
%3D
(:)
S+1
d)
U(?)
%3D

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